SPSolution11-12

SPSolution11-12 - Naik, Sameer V. Solution for Special...

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Naik, Sameer V. Fall 2009 1000 Solution for Special Problem 11 Given: - Steam inside piston-cylinder device undergoing constant volume and constant temperature processes Find: - P-v diagram - Pressure (bar) at the end of constant volume cooling process - Internal energy change (kJ) for the constant volume cooling process - Pressure (bar) at the end of constant temperature process System: Saturated Vapor Initial State P 1 = 20 bar Assumptions: - Negligible leakage in piston-cylinder device, i.e. closed system (mass constant) - Quasistatic processes Basic Equation(s): V m v = f g f y y x y y = Solution: (a) The processes are shown on the P-v diagram below.
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Naik, Sameer V. Fall 2009 1000 (b) From Table A-3, for saturated vapor at state 1 with P 1 = 20 bar, we have: v 1 = 0.09963 m 3 /kg and u 1 = 2600.3 kJ/kg. The mass contained in the piston-cylinder device is: 3 3 0.03 m 0.3011 kg m 0.09963 kg m == . For constant volume process, v 2 = v 1 = 0.09963 m 3 /kg. From Table A-2, at T 2 = 200°C, we have: v f < v 2 < v g SLVM at state 2. Thus, the pressure at the end of constant
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This note was uploaded on 05/15/2010 for the course ME 200 taught by Professor Gal during the Spring '08 term at Purdue.

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SPSolution11-12 - Naik, Sameer V. Solution for Special...

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