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Unformatted text preview: Naik, Sameer V. Fall 2009 1000 Solution for Special Problem 17 Given:- Steady state flow of ideal gas through a given device Find:- Change in enthalpy (kJ/kg) of the gas - Temperature ( C) of the gas at the exit System: Assumptions:- Steady state steady flow - No heat transfer - No work interaction - Negligible change in potential energy Basic Equation(s): 2 2 . . . . 2 2 CV i e i e CV i i e e CV inlets exits dE Q W m h gz m h gz dt & & =- + + +- + + Solution: (a) Applying the energy balance for the steady flow device, we have: 2 2 . . . . 2 2 CV i e i e CV i i e e CV inlets exits dE Q W m h gz m h gz dt & & =- + + +- + + i.e. 2 2 2 1 2 2 1 2 m 44,987.5 2 s h h -- = = - . However, 2 2 m J 1 1 s kg = ; hence, the change in specific enthalpy of the gas is: kJ 45 kg h = - = - = - = - ....
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This note was uploaded on 05/15/2010 for the course ME 200 taught by Professor Gal during the Spring '08 term at Purdue University-West Lafayette.
- Spring '08