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SPSolution25-26

SPSolution25-26 - Naik Sameer V Solution for Special...

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Naik, Sameer V. Fall 2009 1000 Solution for Special Problem 25 Given: - Water executing Carnot heat engine cycle Find: - Pressure, temperature, specific volume, specific internal energy, specific enthalpy at all four states within the cycle - Heat transfer and work (kJ) for each process in the cycle - Thermal efficiency (%) of the cycle - P-v diagram System: Assumptions: - Carnot cycle executed in a closed piston-cylinder device - Negligible changes in KE and PE Basic Equation(s): Q W U KE PE = Δ + Δ + Δ 1 cycle C thermal H H W T Q T η = = Solution: (a) At state 1, we have water at 40 bar and 15% quality. Using Table A-3: ( ) ( ) 3 3 3 3 3 1 1 m m m 1.2522 10 0.15 0.04978 1.2522 10 0.008532 kg kg kg f g f v v x v v = + = × + × = ( ) ( ) 1 1 kJ kJ kJ 1082.3 0.15 2602.3 1082.3 1310.3 kg kg kg f g f u u x u u = + = + = ( ) ( ) 1 1 1 kJ kJ kJ 1087.3 0.15 1714.1 1344.42 kg kg kg f g f f fg h h x h h h x h = + = + = + = At state 2, we have saturated vapor at 40 bar. Using Table A-3: 3 2 m 0.04978 kg g v v = = , 2 kJ 2602.3 kg g u u = = , 2 kJ 2801.4 kg g h h = = Process 2-3 is adiabatic. Applying energy balance, we have: 23 23 23 q w u = Δ
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