SpecialProblems33-35

# SpecialProblems33-35 - Special Problems for ME 200 Fall...

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Special Problems for ME 200 – Fall 2009 Special Problems 33, 34, and 35 Due Monday, November 30, 2009 SP33: A two-stage compressor is designed to minimize the work input requirement. Air flows through the system and data for air at some locations within the system is shown in the figure below. Both compressors can be considered to be adiabatic and pressure drop across the intercooler can be neglected. The isentropic efficiency for the first stage of compression is 90%. The intercooler rejects heat to a reservoir at 27 C. Consider variable specific heats for air. P 1 = 100 kPa T 1 = 300 K P 2 , T 2 P 3 = P 2 T 3 = 340 K P 4 = 15.4 MPa T 4 = 750 K Compressor Stage 1 Intercooler Compressor Stage 2 T surr = 27 C Q cooler (a) Determine the amount of heat rejected (kJ/kg) in the intercooler. (b) What is the isentropic efficiency of the second stage compressor? (c) Compute the total entropy generation (kJ/kg-K) for the system. SP34:

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## This note was uploaded on 05/15/2010 for the course ME 200 taught by Professor Gal during the Spring '08 term at Purdue.

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SpecialProblems33-35 - Special Problems for ME 200 Fall...

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