Ma 449: Numerical Applied Mathematics
Model Solutions to Homework Assignment 1
Prof. Wickerhauser
Exercise 9(a*) of section 1.1, p.12
Let g(x) be the integral from 0 to x of t^2 cos(t).
Then by the Second
Fundamental Theorem of Calculus (2FT), we have g'(x)= x^2 cos(x).
Exercise 9(b) of section 1.1, p.12
Let g(x) be the integral from 1 to x of exp(t^2).
Then by the Second
Fundamental Theorem of Calculus (2FT), we have g'(x)=exp(x^2).
But
the function we need to differentiate is f(x)=g(x^3), so we use the
chain rule: (d/dx)f(x) = (d/dx)g(x^3) = 3 x^2 g'(x^3) = 3 x^2 exp(x^6).
Exercise 11(b*) of section 1.1, p.12
Factor out 2/3 and apply the geometric sum formula to get 1/(1-1/3)=3/2
for the sum of 1/3^n from n=0 to infinity.
The result is 1.
Exercise 11(c) of section 1.1, p.12
Write 3/(n(n+1)) as 3*[ 1/n - 1/(n+1) ] to get a telescoping series:
each term -1/(n+1) is cancelled by the 1/n term for the next n.
Since
1/n tends to 0 as n tends to infinity, the only surviving term is 1/n
for the first value of n, namely n=1.
Thus the sum is 3*(1/1) = 3.
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- Fall '09
- Wickerhauser
- Math, Applied Mathematics, Fundamental Theorem Of Calculus, Binary numeral system, Decimal, Summation, UCI race classifications
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