EG243 Control Systems 08 AnsQ1 - 4 5 20 5 ramp 1 then t s t t s s s E s R s R s GH s s s s f t sF s i R s s e t ii R s s e t arg(0 4 K GH j 0 arg 180 GH

Page : 1 of 7 SCHOOL OF ENGINEERING EXAMINATION MODEL ANSWER SHEET Paper Title: Control Systems Paper No : EG-243 MAY/JUNE 2008 Examiner(s) : JSM Question No Marks JSM/EG-243_08 1. ( 5) ( 1)( 2)( 10) K s GH s s s s (a) [5 marks] (b) (c) 2 10 ( ) t t t c t Ae Be Ce (d) Nyquist diagram: (e) K/4 -1 Re(GH(jw) ) Im(GH(jw) + 0 1( 10) ( 1)( 2)( 10) 1( 5) 10 2 / 5 20 5 C j j R j j j j C j R 0 2 1 ( 1)( 2)( 10) ( ) ( ) 1 ( 1)( 2)( 10) ( 5) FVT : ( ) ( ) 20 ( ) step: ( ) 1/ then ( )

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 4 / 5 20 5 ( ) ramp: ( ) 1/ then ( ) t s t t s s s E s R s R s GH s s s s f t sF s i R s s e t ii R s s e t ( ) arg(0) 4 K GH j ( ) 0, arg( 180) GH j [5 marks] [5 marks] and ( 5) ( ) ( ) ( 1)( 2) ( 10) K s G s H s s s s [5 marks] + + R G/(1+GH) J/G R + E G J _ H whence . 1 1 G J GH G R C [5 marks] C...
View Full Document