EG243 Control Systems 09 AnsQ1

# EG243 Control Systems 09 AnsQ1 - ocus-1 jW Im(GH(jw))...

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Page:! of5 SCHOOL OF ENGINEERING EXAMINATION MODEL ANSWER SHEET Paper Title: Paper No: EG-243 Question No MAY lJUNE 2009 Examiner(s): ISM Marks 1. (a) (b) c (s)= K R (s + a)(s + b)(s + c) + K [2 marks} [2 marks} (c) Type 0 system so: K K =- P abe' Thus sse for: unit step = 1/( 1+Kp) = abc/(abc+ K) and ramp ~ 00 (d) Nyquist diagram [5 marks} . K (j) -). 0 GHCJ(j)) -). -arg(O) abe OJ ~ 00 GH(jOJ) ~ 0 arg( -270) ~ ~ .. a(,.e.- a 0 (aH6AI ams 0 iI.:J ~~~) 11 J..'1o
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Unformatted text preview: ocus-1 jW Im(GH(jw)) K-arg(O) abe [5 marks} [6 marks} .-.' ..: ~ .:. .. ::::::~ :::::::::::::::::::::::::::::::::::::::::::::::::::::::::,'" "..-,.",,,Pipduct of these 3-~ . .. <:. .cf vectors give value ofK at stability limit [5 marks}...
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## This note was uploaded on 05/17/2010 for the course ENGINEERIN EG 243 taught by Professor Murphy during the Spring '10 term at Swansea UK.

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