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Unformatted text preview: E(sample mean ) = μ =5 and the standard error = σ/√n = 2/√40. 4.) State the level of significance and the decision rule: If Pvalue the hypothesis testing of the mean is less than α, then reject the null hypothesis. 5.) State the conclusion in the context of the problem. MINITAB: OneSample Z: Days missed Test of mu = 5 vs < 5 The assumed standard deviation = 2 95% Upper Variable N Mean StDev SE Mean Bound Z P Days missed 40 5.450 2.037 0.316 5.970 1.42 0.923 There is insufficient sample evidence to support he alternative hypothesis, mu < 5, the number of days missed is below the national average....
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This note was uploaded on 05/17/2010 for the course MATH 246 taught by Professor Applebaugh during the Spring '10 term at University of Toronto.
 Spring '10
 Applebaugh
 Math, Statistics

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