Math 246 Project 8 Sample KEY (1)

Math 246 Project 8 Sample KEY (1) - E(sample mean = μ =5...

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Project 8 KEY A local school district claims that the number of school days missed by its teachers due to illness is below the national average of 5. A random sample of 40 teachers provided the data below. At the 0.05 level of significance ( =0.05), test the district's claim. Assume = 2. Days missed 5 4 5 5 4 8 4 5 6 4 3 2 8 2 9 6 6 3 4 8 3 6 5 7 3 6 5 10 4 3 6 7 5 5 7 10 8 7 4 6 1.) Define the parameter(s) of interest. is the mean days missed. μ 2.) State the null : ____ mu = 5 ____________________________ State the Alternative : ___ mu < 5 _______________________ 3.) State assumptions, verifications, etc.
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Anderson-Darling p-value = .111 greater than .05 therefore the sampled population is Normally distributed; the box plot does not contain any outliers. The sampling distribution of the sample mean is approximately Normal,
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Unformatted text preview: E(sample mean ) = μ =5 and the standard error = σ/√n = 2/√40. 4.) State the level of significance and the decision rule: If P-value the hypothesis testing of the mean is less than α, then reject the null hypothesis. 5.) State the conclusion in the context of the problem. MINITAB: One-Sample Z: Days missed Test of mu = 5 vs < 5 The assumed standard deviation = 2 95% Upper Variable N Mean StDev SE Mean Bound Z P Days missed 40 5.450 2.037 0.316 5.970 1.42 0.923 There is insufficient sample evidence to support he alternative hypothesis, mu < 5, the number of days missed is below the national average....
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Math 246 Project 8 Sample KEY (1) - E(sample mean = μ =5...

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