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Unformatted text preview: Note that decision maker 1 is the 5 th percentile; so, using the TI 83/84 invNormal(0.05,105,2.03) the decision maker 1is 101.66. The decision maker 2 is the 95 th percentile; so, using TI 83/84 invNormal(0.95,105,2.03) the decision maker 2 is 108.34. Decision Rule (classical approach): If the sample mean is less than 101.66 OR the sample is greater than 108.34, then reject the null hypothesis. Otherwise, do not reject the null hypothesis. POWER: Using TI: normcdf(∞, 101.66,E , 1 . )+ ( . , 2 03 normcdf 108 34 ∞ , , 1 . ) 2 03 Possible values of (assuming the alternative is true) Power 111 .90544 110 .7940 109 .6284 107 .2593 106 .1410 104 .1410 103 .2593 99 .90544 98 .9646 97 .9893 Construct the Power Curve: 112.5 110.0 107.5 105.0 102.5 100.0 97.5 95.0 1.0 0.9 0.8 0.7 0.6 0.5 0.4 0.3 0.2 0.1 MEAN POWER Scatterplot of POWER vs MEAN...
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 Spring '10
 Applebaugh
 Math, Statistics, Probability, Null hypothesis, Statistical hypothesis testing, decision maker

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