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# quiz4ans - (b State transition table S 1 S S 2 1 00 111...

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ERG2020A: Digital Logic & Systems (Fall 2007) Quiz #4 Suggested Solution 1. Based on the characteristic table of SR latch, we have the following excitation table: C W X Y S R 0 X X X 0 0 1 0 0 0 0 0 1 0 0 1 0 1 1 0 1 0 0 1 1 0 1 1 1 1 1 1 0 0 0 1 1 1 0 1 1 1 1 1 1 0 1 1 1 1 1 1 1 0 X W C Y CW XY 1 1 1 1 X W C Y CW XY 1 1 1 1 1 1 1 S = m (11 , 13 , 14 , 15) = CWX + CXY + CWY R = m (9 , 10 , 11 , 12 , 13 , 14) = C X + C W + C Y S R Q Q W X Y C Q

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2. (a) The transition table S 1 S 0 X S 1 S 0 Z 0 0 0 0 1 0 0 0 1 0 0 0 0 1 0 0 1 0 0 1 1 1 0 0 1 0 0 0 1 0 1 0 1 1 1 1 1 1 0 0 1 0 1 1 1 0 0 0 (b) The Moore model state diagram 00/0 01/0 10/0 11/1 0 1 0 1 1 0 0 1 (c) The next state equations: S 1 = m (3 , 5) = X ( S 1 S 0 ) S 0 = m (0 , 2 , 4 , 5 , 6) = X + S 1 S 0 Z = S 1 S 0 X Implementation: X D Q Q C D Q Q C CLK Z S1 S0 S1’ S0’
3. (a) The state diagram (Moore Model) A/0 B/0 C/0 D/0 E/0 F/0 G/1 2 0,1 2 3 0,1,3 1 2 2 3 2 0 0,1,3 0,1,3 2 2 0,1 0,1,3 1 (b) The transition table [Encoded states also accepted] 0 1 2 3 A A A B A B A A B C C A A B A D A E B C E A F B A F A A G A G A A B C 4. (a) 3 flip-flops are required.

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Unformatted text preview: (b) State transition table S 1 S / S 2 1 00 111 001 01 010 100 10 110 101 11 011 000 (c) Next state expressions: 1 1 1 1 1 1 1 1 1 1 1 1 S2’ S1’ S0 S1 S2 S0 S0 S0 S2 S2 S1 S1 S ± 2 = S 1 S + S 2 S + S 2 S 1 S S ± 1 = S 2 S ± = S 2 S + S 1 S + S 2 S 1 S Implementation: D Q Q C D Q Q C CLK S1’ S0’ D Q Q C S2’ S2 S1 S0 C1 C0- END -...
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