ch02 - Chapter 2 Elements, Compounds, and Chemical...

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Chapter 2 Elements, Compounds, and Chemical Reactions Multiple Choice Section 2.1 1. How many atoms are there in one formula unit of NiSO 4 7H 2 O? a. 9 b. 14 * c. 27 d. 28 e. 33 Section 2.1 2. Which one of the statements below is true? a. When two atoms combine, they do so in definite proportions by weight b. When two different compounds combine to form an element, they do so in definite proportions by weight * c. When two different elements combine to form a compound, they do so in definite proportions by weight d. When two molecules combine, they do so in definite proportions by weight e. When two different elements combine to form a mixture, they do so in definite proportions by weight Section 2.1 3. The relative number of atoms of each element in a particular compound a. is always l:l b. is the same as the density ratio c. is the same as the weight ratio * d. is definite and constant e. cannot be determined experimentally Section 2.2 4. A naturally occurring element consists of three isotopes. The data on the isotopes: isotope #1: 46.972 u , 69.472% isotope #2: 48.961 u , 21.667% isotope #3: 49.954 u , 8.8610% What is the average atomic weight of this naturally occurring element? * a. 47.667 u b. 47.699 u c. 48.629 u d. 48.667 u e. 48.961 u Section 2.2 20
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5. A naturally occurring element consists of three isotopes. The data on the isotopes: isotope #1: 146.9672 u , 64.792% isotope #2: 148.9638 u , 26.117% isotope #3: 149.9592 u , 9.0910% What is the average atomic weight of this naturally occurring element? a. 49.254 u * b. 147.76 u c. 148.63 u d. 148.67 u e. 147.80 u Section 2.2 6. A naturally occurring element consists of three isotopes. The data on the isotopes: isotope #1: 187.9122 u ., 10.861% isotope #2: 190.9047 u , 12.428% isotope #3: 192.8938 u , 76.711% What is the average atomic weight of this naturally occurring element? a. 64.035 u b. 190.57 u c. 190.67 u d. 192.08 u * e. 192.11 u Section 2.2 7. A naturally occurring element consists of three isotopes. The data on the isotopes: isotope #1: 147.9554 u , 10.563% isotope #2: 150.9496 u , 70.811% isotope #3: 152.9461 u , 18.626% What is the average atomic weight of this naturally occurring element? a. 50.335 u b. 150.62 u c. 150.67 u * d. 151.01 u e. 151.08 u Section 2.2 8. A naturally occurring element consists of two isotopes. The data on the isotopes: isotope #1 68.5257 u 60.226 % isotope #2 70.9429 u ?????? % Calculate the average atomic mass of this element * a. 69.728 u b. 69.743 u c. 69.934 u d. 69.972 u e. 70.141 u 21
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Section 2.2 9. The atomic mass of naturally occurring iron, which is a mixture of isotopes, is listed as 55.847 u . This means that the average mass for the individual iron atoms is a. 55.847 times as great as that of a 12 C atom b. 55.847 times as great as that of a 1 H atom c. 55.847/1.0079 times as great as that of a 1 H atom * d. 55.847/12.000 times as great as that of a 12 C atom e. 55.847/12.011 times as great as that of a 12 C atom Section 2.2 10. The atomic mass of naturally occurring nickel, which is a mixture of isotopes, is listed as 58.6934
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This note was uploaded on 05/19/2010 for the course CHEM 211 taught by Professor Rellima during the Spring '08 term at Wichita State.

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ch02 - Chapter 2 Elements, Compounds, and Chemical...

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