301 HW_3_Solution

301 HW_3_Solution - MAE 301: Engineering Thermodynamics...

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1 MAE 301: Engineering Thermodynamics Spring 2010 HOMEWORK #3 ( Solutions ) Problem 1. Problem 3.37 from the book. Solution: The state of water is superheated vapor. From the steam tables, 6) - A (Table C 200 kPa 50 kJ/kg 2660.0 = ° = = u T P Problem 2. Problem 3.38 from the book. Solution: The state of water is compressed liquid. From the steam tables, 7) - A (Table C 100 MPa 5 /kg m 0.001041 3 = ° = = v T P Based upon the incompressible liquid approximation, 4) - A (Table C 100 MPa 2 C 100 @ /kg m 0.001043 3 = ° = = ° f T P The error involved is 0.19% = × = 100 001041 . 0 001041 . 0 001043 . 0 Error Percent Problem 3. Problem 3.34 from the book. Solution: The initial specific volume is /kg m 1989 . 1 kg 1 m 1989 . 1 3 3 1 1 = = = m V At the final state, the water occupies three times the initial volume. Then, /kg m 5967 . 3 ) /kg m 1989 . 1 ( 3 3 3 3 1 2 = = = Based on this specific volume and the final temperature, the final state is a saturated mixture and the pressure is 4) - A (Table C 3 @ sat 2 kPa 0.768 = = ° P P
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2 Problem 4. Problem 3.32E from the book.
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This note was uploaded on 05/19/2010 for the course MAE 301 taught by Professor Hassan during the Spring '08 term at N.C. State.

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301 HW_3_Solution - MAE 301: Engineering Thermodynamics...

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