301 Test_2_Solution

# 301 Test_2_Solution - SOLUTIONS MAE 301: Engineering...

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MAE 301: Engineering Thermodynamics I Spring 2010 Test 2 (15% of final grade) March 11, 2010 Problem 1. (25 points) Air is confined to one side of a rigid container divided by a partition. The other side is initially evacuated. The air is initially at P 1 = 5 bar, T 1 = 500 K, and V 1 =0.2 m 3 . When the partition is removed, the air expands to fill the entire chamber. Measurements show that V 2 =2 V 1 and P 2 = P 1 /4. Assuming the air behaves as an ideal gas, determine (a) the final temperature, in K, and (b) the heat transfer, in kJ. Solution: W Q U mRT PV = Δ = kg K kgK kJ m kPa RT V P m mRT V P 7 . 0 500 / 287 . 0 2 . 0 500 3 1 1 1 1 1 1 = = = = K kg kgK kJ m kPa mR V P T mRT V P 250 7 . 0 / 287 . 0 4 . 0 125 3 2 2 2 2 2 2 = = = = ( ) 1 2 0 ; u u m U Q W W Q U = Δ = = = Δ Table A-17 kg kJ u K T 5 . 359 500 1 1 = = kg kJ u K T 3 . 178 250 2 2 = = () kJ kg kJ kg u u m Q 127 ) 5 . 359 3 . 178 ( 7 . 0 1

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## This note was uploaded on 05/19/2010 for the course MAE 301 taught by Professor Hassan during the Spring '08 term at N.C. State.

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301 Test_2_Solution - SOLUTIONS MAE 301: Engineering...

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