{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

exam2_sol_sp10

exam2_sol_sp10 - Physics 101 Classical Physics Spring 2010...

This preview shows pages 1–3. Sign up to view the full content.

Physics 101 Classical Physics Spring 2010 Exam 2 Solutions Instructions : The answer sheets must be handed in as soon as time is called. You have until 10:20am. Answer the following four multiple choice questions. Each question is worth 4 points. 1. A ball of mass 0.3 kg hits a wall and rebounds. Initially the magnitude of the ball’s velocity is 7 m/s, but after rebound the magnitude of the velocity is 5 m/s. What is the impulse imparted to the ball by the wall? (a) 1.8 kg m/s, (b) 2.1 kg m/s, (c) 3.6 kg m/s , (d) 0.6 kg m/s, (e) 1.5 kg m/s The impulse is equal to the change in momentum, so I = Δ ~ p = m ( ~ v f - ~ v i ) Defining the final velocity to be in the positive direction, I = m (5 m/s - ( - 7 m/s)) = (0 . 3 kg)(12 m/s) = 3 . 6 kg · m/s 2. An object initially at rest breaks into two pieces as the result of an explosion. One piece has twice the kinetic energy of the other piece. Which of the following is the ratio of the masses of the two pieces? (a) 1:1, (b) 2:1 , (c) 4:1, (d) 16:1, (e) more information is needed Since the total momentum is conserved and initially zero, the velocities of the pieces must be along the same axis with opposite signs. So, momentum conservation gives m 1 v 1 = m 2 v 2 v 1 = m 2 m 1 v 2 We are given that the kinetic energy of one of the pieces is twice that of the other. 2 T 1 = T 2 m 1 v 2 1 = 1 2 m 2 v 2 2 Plugging in the expression for v 1 above this becomes m 1 m 2 2 m 2 1 v 2 2 = 1 2 m 2 v 2 2 m 2 2 m 1 = 1 2 m 2 m 2 m 1 = 1 2 So, the mass ratio is 2 : 1 . 1

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
3. A flywheel rotating with an initial angular velocity of 12 rev/s is brought to rest in 6 s. If the angular acceleration is constant during this time, what is its value? (a) -4 rad/s 2 , (b) -4 π rad/s 2 , (c) -2 rad/s 2 , (d) -1/ π rad/s 2 , (e) -72 rad/s 2 Since the angular acceleration is constant, α = Δ ω Δ t = - 12 rev/s 6 s 2 π rad 1 rev = - 4 π rad/s 2 4. The Earth wobbles—the axis about which it rotates each day actually rotates its direction over time (this is a phenomenon called ‘precession’). While right now it points toward the star Polaris (the North Star), in 13,000 years it circles around and and will eventually point toward the star Vega in the opposite part of the sky. 13,000 years after that, it will have circled all the way back and point toward Polaris again. Which of the following statements is most likely to de- scribe why this does or does not violate the conservation of angular momentum? (a) The speed of rotation does not change, so the angular momentum is constant and therefore conserved. (b) Angular momentum does not have to be conserved, because the Earth is in space, far away from anything else. (c) The Earth is being acted on by an external torque from the gravity of the Moon and the Sun, and so this changes the Earth’s angular momentum. (d) Angular momentum is conserved, because the axis eventually gets back to where it started so the net change is zero.
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}