Class_notes_week2

Class_notes_week2 - Saab Prpxbbméflfi Oganczuiias ma’...

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Unformatted text preview: Saab? Prpxbbméflfi Oganczuiias ma’ cfééigfl aflwypész’yméuw 5.51/15 {Ség Of [:33 mm My (sack/d] m’améyfirg 7 ($1345? maméam. 4' CC} 56am??? gwmmcgg Vb i (£422 74?{ L34”j/2N‘@”\ Exam], § i vaq 35%: céuva ijéa‘flés awe beamn 53%;: 5mg Mgmfiaéfi' SUCé‘q ékuwg’é’bk‘sri’fij NC?- my“ heéfijj gweigé’i {gwfig} 5&5:ch b C a? {a7 ngukfif wwa Mafia h) w(£m(a{’£ (a) Q’Lvlflkg /}1Wym&{ [mg] a W awgga) §Arasmg Zn»! (AL 55mg; «:1; ' a“; . ' _ i i ' ,' ”,2 2:15; I Z .. Sm mm? mmfite pmgmg New”; MW g méfimdafog; Oué’flhad qjm fee: {*6} ’ $39,.” I E l, game” C’DWLQ 28723 fig§fiuungs33 , % Wm the assembly and ioading of Prab. '1 10 dc mag: shearing stress in the pin at C, (I?) _the average bearing stress at C m mem- - bar BC (6) the averagé bearing stress at B m member BC. 21:3,wa rmum‘i Yéflcém 36mg :15” C I“ .W’Mfinfimm' Gil/M 1L9 (0;) Beafigm? gfiegs (3% 6 : VM‘“ ? '9 d : 7 J P 5' WW? 61: i: (:3 Us) Sham sham {23f babé cult i: “#813 fwgbafi? MW EV 3 j] C ’31 Swazi (“33 Deal-“fin mwdamg7m5‘ ‘ n . 7%,6 (Livev‘mQ-ie: fifiahgtk @an YM‘KWW“! mym ' mimiaf'ea axfggygme Matty; 1:3 ax mafiarzfiml, ,‘éxm figfl? f ‘ W (M ‘ avam é cMmQJéa {Imé‘fxfi f) yam ; Masmbéxg {Ma QE’E‘Z‘K 91¢; wiffi‘ ‘m-me 9m awméé‘? Fake-am}an F Tm!" 30.5» F15 . 3n Wag? «Mark dawn. . onM MM! 033%? LL: W'gawwiiw W? Va‘wx s‘a 23% Law $3 {1&3 big/1:5 D- ' ’ 4 i dxs’mg’mg aUex,-m%c, Lam; if» 5 Linfi 0)? 93;, ,5 W F #53 ~ - - , ; 1.331n the sisal structure shown, a 6—m—diameter pin is used at C and ‘ IO—mm—diameter pins are. used at B and D. The ultimate shearing stress is 150 , :} ED Ag K: MPa at all connections, and the ultimate normal stress is 400 ‘MPa in h'nk 3D. ~;= KnoWin'g that a factor of safety of 3 is dcsircd, determine the largest load P that can be applied at A, Notc that link ED is not reinforced amund the pin 1301651 Difdmfg H V Q33 3.; \qu ( \M éra cm. 09cm ”7L? Chafiww‘w “y‘w/M—nmw M" v. W.-.~ww ... »M#.u..~~...w « 'w-.—IWM»W.W ” "‘1 g¢bii 3, A l 3 ”,9; 1w “3}“ IF: '/ , 7, Md» “ {a m? WWW/W t a}? a , , qt :3 I I, 1 W8 maam W'xm/éfiyvm; 7T 0“ rad/hm I " cw” (f’fi'zpég » §V\m«/)g wb‘ Diflfwmw‘gwfi“ m at. 533’ (if? 0 9n #ayb‘awfmv/ 151% My}; Maw {H5214 “ Ckafaf‘ev LL c/zmi’ U‘WM’M [CMMJN mog’c; ma .' «5‘ / Shem w)? CAamfla w: p mi? CAan S mi% 4%! (M 8km ) {In §MF€5N0 $6? wit; 1 5 ‘ Laggggfi' 281M; Mam/jag m 5 if: J S‘Vfi/gfiffit a} fluid wavy w may} , 5&5 2&2, NWmfit/fixxfl/ >~MWMMWMMMW~MMVW _ fly... ”4......N, N, ‘4uu>uwau>vw.—~p.v*_~»~"m‘ my..-» 1% ”T , l / 7”" g L l I: W 1] l i J 3 1' I, (“:7 {T T ,’( \ I ,’ I 1 J I” N “d L/J (T f ‘ 2Q 'T \L" A T J’ .2 P P (my C1) (9553:}. 5 Na gm (m £4355 L’ J I w? 0% akawé MN QRMT) { \/ V Uw—Lg'“ , ‘VT 1:: V/‘ M . ”*Wi’wg W 1:) . “ as) m, m: mg“? “BM/42» JV! [fiwv J dg/Afizéamafi {5 Z? (Y: j; t V ffla (but: §aw a u ’ ' '7 Tam Q3?“ Caugag km .§C¢.ML fikafljfl ELM O'h my: C: T {3 / OWE P 3 L‘jwjr‘i y‘ 179%? T T [T :3? rkmhji ‘ ' T - A 2% “ 4 " . Mme 7m 13f bi WW myzmd MM NWMD‘L/Ql‘bkak £9me E - CA -V‘x LVN 15m fix ~ I . / ‘7, 5 , V 3%“ (Damaéaxfnw a’ Wm \hafif IL? W? 371% Jifgw" ; 35" (1535? {fflm 03g, ayyzag $, fiwlm‘mumggg My? 6%}: 50% H“; 37/ W53 wwrid MAW fi - M ., a}? Narmamm I; I W Mi w‘ Cf?“ . A%%0 firm £5”; ham CAM Vim W ‘vfijltuwawnrw‘w‘libouiw wwwmwuwfirwynMu-Jw‘u M I Sex/ma- .: Maw \t / Vagafifl 3 M V3 6% 3%.333 J55: MMY A?) Cum mkma 113% M W, m3: MW, 533 {3 3 _ 3333,23? , 37M Ma» ,3: a m M (3:23 { 4 1.: m A): :3me M a)? [bfmaéfi’mfl m Lac/@551?” ’53 ’53“: “’ fimyra“: { T Eff/1%? 333.9333“ 5? (4553)!” ”WWW”; 333 M w J w w i 3' Qt vvw a 55 {33,333 géwé’L‘f-w- “flaw 3’ 6kg) é; (0738 g (”fr {523; a d {366% V“; J); ‘ .1 - , * “ “TM“ 4%,“ Lg 433 M 43* WW 1 {way PM @313 3 {3,35 [,2 L3» 3 , V a 1,. ,» CY“ W ”2‘! I L,“ 3,. ”fl HachA 5m 54% w r ”ET MT) t) [33% m (A) (1 ‘ I “ . Mafia; 3 .mm x“ (f w qE/flgéxffwvgij/m&lf 5 333m? (31le 6:; v» L i a) V“ I} 2'2 A 60-m~long SCPCI w' ’ ‘ w', « me is sub mad to 6 kN ‘ A that E ~ 100 GPa and that the: length of 13hr, rod inc fitfinmle fox-cg, Knowmg (a) the smallest diameter ihm may be 561 t cl reasus'by 48 mm, défCrminc ding nomal stress, 6C 6 for the WW" (5) the “”33”” 5'“ » w» <5“ 5*“ y W,» ““‘ r “wflwawm {$3 P 3:: W ““ng % _ j 2.8 A square aluminum bar should not stretch more than 1,4 mm when" \t ls subjected to a {smile loadl Knowing that E = 70'GPa'and' that ihe allow— dctermine (a) the maxlmum allowable Length - lien if the tansile load strength is 1’20 MPa. requlrsd dim 8 cross sec able tensile ensions of th 9f the pip}; (b) the IS 28 m. » 3%wxw‘x . Dflr‘fiégw wwdl” gmfiw‘ a P M g M Mg? $ {mm $2,. L m ’ - L :3 Hi» W . ~53; a “:2“? U) a 3525 2.6,»237 M ‘ Ddfimékg Vac/amség [m fire/mink: vg ciguaéa’fg ngflmm <5" CG” gflmfi WW (3A1?!) (was) g _lx’3fia\£§ Wickjl‘éwljxi 60 w] M; x dwioafi. W? 5W?“ fig *A‘QWO" ngmimm 1m .5 g {3gb} w” W WW ; ’ $2. 1 $253 “’7 7 a 9 p {4"}? ' ) *‘= m 3 yfi’fflW’” "‘ ' M“, fix 2. N29; ES agarizébrmmim §u j a m. fig» :1ng W 2.16 A single axial load of magnitude P = 58 IN is applied at and } C of the brass rod ABC. Knowing that E = 105 (Pa, determine the diameter { d of portion BC for which the deflection of point C win bf: 3 mm. E | '1 30 mm : i B , 1 \L‘ C \ 0,8 m‘ \ ( Pay 3;) 2.18 The rod ABC is made; of an aluminum for which E = 70 GM» 90 . - wmm dmmeter Knowing that P = 6 kN and Q = 42 RN. detarminc the deflection of (a) point A, (1:) point B, 0.4 m {SO-mm dhtmeter 1W? W x r" . 9 Ugéajgafe’éj i 9 x 1 l 6 224 Each of the links A}? and CD is made of aluminum (E = 75 6133) and has a cross~sectional araa of 125 mmz, Knowing that they support the rigid mambér BC, datermine the, deflection of point E, w em 63‘ E W3: E: ...
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