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(Fm Jvm‘ak aﬁfﬂggwamﬁ 9% ’ 4’ * 41 51.5w 8:; ii'iév’c’a‘jﬁziéﬁ w i NO ‘1‘ «.5.
NHL f; viii 35 (:1) Determine the torque that can be applied to a solid shaft of 20—min
diameter witheut exceeding an allowable shearing stress of SO MP3, (b) Soive
part (1, assuming that the solid shaft has been replaced by a hoilow shaft of the
same crass—sectional area and with an inner diameter aqua} to half of its own
outer diameter. ' 3.11 Under normal operating conditions, the Bloom’s motor exerts a
torque 01°28 kN ~ In on Shaft AB, Knowing that each shaft is solid, dczm'mine
the maximum shearing stress in (a) shaft AB, (19) shaft BC, (6) shelf»; CD, TB 2 1:41:53 . m
A}; = 09 IN ‘ m / Alf/mm / TD = 0.5 kN  m 46 mm 3.18 The allowable shearing stress is 15 ksi in
rod AB and 8 ksi in the l.8in.diameter rod BC, Neg
concentrations, detei‘mine the largest torque that can the 1.5—inrdiameteI steel
lecting the effect of stress
be applied at A, 51m; B 1 "§~\ ..‘_>\
750 m m\j ([33
K 600 mm
\ MW 3334 Deiermine the largest allowable diamei‘m‘ of a lO—ft=1ong steel rod
(G = 11.2 X 106 psi) if the md is to be twisted through 300 without exceed
ing a shearing SiZ’ESS of 12 ksi. 3,38 The aluminum rod
[JD (0 = 39 GPa). Knowing th
has an inner diameter of 40 mm A8 (G = 27 GM} is bonde at portion CD of the
, defermine the ungis d to the brass rod
brass rod is hollow and
of twist at A. ,3 2,, 3:2 {/15 WW7 {2’3 2‘
‘” 95 :32 r4 gm 39319131314, veﬁogﬁawﬁ x“ 325/1” 3/ , g )
\l WWW"
V V V} d 6/7KNM33333‘{~W
;
3.31123311wa (,1) um i; ‘ ‘ 155’, {"3er
+7: Wm: {524’ VCQZ g 2 r » «::}u§} 3" 32:; ff”? 0:1”gi J"! K0 (3/01,!) 2? » 13,53 The composite shaft shown consists of a S—mm—thick brass jacket
= 39 GPa) bonded to a 40—mm—diameter steel core (Gm, = 7742. GPa).
Wing that the shaft is subjected to a 600 N { m torque determine (a) the
*‘32imum shearing guess in the b12188 jacket (29) the maximum shearing stress
#31: steel 0016 (2) thﬁ angle of twist of B relaiiVe to A. 40 mm ' “‘ t Steel COTE
1T) m S" 3.53? and 3.53 Two solid steel sham are fitted with ﬂanges; that are
then connected by bolts as shown. The bolts are slightly undersized and per— mit a l.5° rotation of one ﬂange with respect to the other before the flanges 2‘ 'ngle unit. Knowing that G = ll,2 X 106 psi, determine begin to rotate as a 51
the maximum shearing stress in each shaft when a torque of T of magnitude 2O kip  ft is applied to the ﬂange indicated,
3.57 The torque T is applied to flange 8.
3,58 The torque '1‘ is applied to ﬂange C. Fig. P357 and 533,58 gin! diameter, are connected by the gears Show,
psi and that tho shaft at F is ﬁxed, detexmine [he
hen a 1.2 kip « in. torque is applied a{ 3.40 Two shafts, such of Knowing that G = 11.2 X 106
angle through which end A rotates w ...
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 Spring '09
 MOORTHY

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