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7_pdfsam_Quizzes 11-14 solutions_1

# 7_pdfsam_Quizzes 11-14 solutions_1 - Phy63 QUIZ 14 pV = nRT...

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Unformatted text preview: Phy63 Spring 20 10 QUIZ 14 pV = nRT pV = NkBT R = 8.314 J/(rnol K) kg = 1.38 x 10-23 J/K inon'aminiogas . Em: Emir = wig-”m? \$3.3m L" “may, Adiabatic expansion PW“: constant. V Ni — 5:19 B (N 1. For a reversible process, the entropy change can be computed according to d8 = ESQ/T. For anirreversible process, however, it is impossible to compute dS, since 3Q for an irreversible process cannot be used (1 point): 3 ® 2. The entropy of a monotonic, ideal gas is given by the Sackur'—Tetrode expression. In an adiabatic compression from initial volume V- to a ﬁnal volume Vf, the change 1n entropy is given by (2 points): {Hint——Use the equi- parn'tion theorem for the energy, E, the equation for adiabatic compression, and the ideal gas law. Note '1] = 5/3.] a. ann(Vi/Vr) ag- ~ lsN M[Vi(%j :1 LN M££¢C§L> ] b. Denim/vi) c. sternum/vi) ‘ '= kN M[E(§i>%] g N T d. nR anm) .0 V1 TL>Y4 3,1 2 .. 5W m[\$:((%£§> )j 1‘64": 3; ' :mni : o ...
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