{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

9_pdfsam_Phy63S10-Q1-4-Solutions

# 9_pdfsam_Phy63S10-Q1-4-Solutions - P113763 Spring 2010 1...

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: P113763 Spring 2010 1,! = (02an k=2nl7t VZM \J (A. : 5‘- Total phase- or path—difference conditions for interference (in units ofl): (l) 0, 7L, 27L, 37L, (2) M2, 31/2, 51,12,712, For standing "waves: (3) 1/2, 3M2, 51/2, 712, (4) M4, 3M4, 5M4, 7M4, Normal modes: (1) n0], /2) = L ; (2) (2n+1) 7L“ /4 = L (n an integer) 1 = again? 10 10g (1/1,) ' f’ = (v +5 V1)/(v — v;) r 2Acos[21n|f1—f2|t/2] 1. A one meter long guitar string, held under tension, is ﬁxed at the two ends (cannot move at the ends). A guitarist plucks it in the middle to make a note. The excited normal modes are predominantly even harmonics of the fundamental (1 point): . o 2. Two Doppler shifted frequencies f1 and f2 are compared. With both source and detector stationary, the frequency of the sound is f. The frequency fl is measured when the source is stationary and the detector is on a car approaching the source at V6. Then, .152 is measured when the detector is stationary and the source is on the 'Car moving away from the detector. The speed of sound is lOvc. It is found that (2 points): ®r1>r2, and f1=1.1f, f2=f/1.1 b. f1>f2,and f1=f/0.9,f2:r/1.1 c. f1<f2,and f1=1.1f, f2=f/0.9 a. f1<f2,and f1=f/1.1, f2=f/0.9 e. flzfz, and \$20.9 f, f2=0.9f. ...
View Full Document

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern