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Unformatted text preview: in this situation. However, if the value of Y is known but it does not tell anything about the value of X , then learning the value of X in this situation will convey the same number of bits as in the situation where the value of Y is not known. That is H ( X j Y ) = H ( X ) in this situation. Thus intuitively we have that H ( X j Y ) & H ( X ) with the equality in the case that X is independent of Y . 5. 2.7925 6. 1380 2...
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