Assign3sol - 8334 3:9 ‘53 ‘mn'J—d “5%1 5540- some...

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Homoaw‘ow DE $3+2|1 :0 e143, “mm AfiksCe’zf Assumu A“: A2“ +8249}; AW” M ”u DE “0””) ’3; + 2%? : Ae°‘+ 8e“+ B’XSK-b- 2(Ae"+ Bxe’q :- ’xe" 8C6uxfll WCCMTS .1 A +B+2R= O (D CCG‘H!‘ 13‘qu {5+ 25 = 1 ® (" " xe"\ ®=> B=V3 5 ©=z> 3A:—B=-‘/3 —3> A= -Y9 M _ _. x . . ‘ 4%? 1/9 8.9‘ 4-13- ’Xf inm‘d edema/1a.}: 00‘..qu ray 9—; 43.1 \u) .1»; 1M WM 51‘ 1M cad t mwuuim %ML§ ‘t.’i Cb rumou-Ui g‘rOM WA Qm-nau- W Huflw‘; Lang flmfl oYmm 6;; : —‘)’Q(T- TA} , pm Tn Ls Th mbufid temp,33‘ h wad. Tho) = 4,24“ c. (Ln'JCaJ) Temp-3 .A‘so, 1143: 2452, The, DE Cam b). an'thd 00\U-0JJ~ ‘O‘a hflvnfi (I? = T“TA : So 2 $1 : d]: fium wdv 0L3:-¢~Lé_ ,thTk 505- 01.- e‘kt. qulsmqu) ”rm: :1. + 557: e'k‘)‘. To gum. 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Swahén 58 mm is 3m: gm— fact—e 4M). d1 Texan, W 3: $1 Omd -t= tk ) we Qxau—e. % -.—.- Tafltk - “373 (1-62“ 393%) ) w’Mah 2:5 mud" be SDI'Jed (501: We un'Cume/ng chm__‘t—_Lbn is whamm Guu. omuaL Camdd'iem md 8m 01;:0 LuJ'Lon To exxsT. Ludln a LJUJ. mod? we Com, m- GD Q L TL T at I “ma cow). em 0 (i—e _—_hd)_ k d mat-A _ 91 £100 \—’\/—‘ \Wg . -. 3cm {3&0 362‘). 53(4) |$ ‘1 Pmabo‘a. wlflw mflnupis 0J4”) ”3+6 0 . :30) 1 9+ Rosa. mCUx #PLTZ {£1 “'1' “t“ “am-L5. 37* fits moux mwfi" LQUI 0.914304. ha} (4”). eth a! L'e we wot M7l-e ‘ZM; CQeonlfl ouckMeinit's / y. 1;;- CM: lwmks) thSKCafl 9: -t,,ca.m+be too smam“ M'leVKj Pmlo LQYVL Usmj Wamm ImfbrMoL+won 21% 1' (1 £76144?) M.—I_\~ )-(M:) .1)(_/;’{ 2-00 u’!’ ow W‘ (O) 1' 3 Ooj. 42:0 nflvd'V'a-l'mw m C1 _ I GDCLQ Ry].— CUT-Ck 32, "HUI. DE. “+13 39+ A 5%(% -' 200)) Or, Salk/i. q; cH.’ _ ‘ repairable or mud/x \s equa‘zvx++o fi<M- Zoo): gig—(M 20o) “max 'Da H By t‘l\§Q—QC:\'\OV\) M’ZOO 2: C€_§—° Witt) '5 200 + £6.65 mo, L27 Ic TLM”; vHM. amouw+ wa grow/‘45) Org Std-[— 0+ 4m»; ‘t‘. Ame}? v MWXM [:3ng Le} 1%) (qcesun‘r AYLL mas, 0; *\‘£’- 3g): m m Stud: \Ae.‘ (ii-— rm‘xe. xx v mm m3. N0 361?, \5 R3.) $334 $0 V032. M 7 O- .. \M\N3€5 " “3”. mix ‘ We.“ eowL m r432. ue. &ro.k 1 “was a; o~ $o\~\}€-n WL-‘xL Qufittaxttms‘ on X , dame. \J :, *Lo, wok.“ V 5‘ 3% $ka bubs om W33. 3. “m “3“ -— 29% \A‘C‘Q \J = 9.00 L '\' K1 L/m;\‘\ (ILMRV\Q5\ —. loo Ar t _ ) ‘ So we. you: “we. me Q 3 ”A; At 100*t . 1M?) \3 Srd?u<§=\c.l m3 ~31A3~S 5 fl =— j “'3‘ At goon; =7 9% \x\ . '1 9M \Jxooxfl "r C.‘ '57 L1 = 31-. (looHA—a A? C\ =7 K: Ck £260+t331 lfikOMwD) flare, OJ’Q— AOODFM; 0% A32. k ““3. M, $0 XLOytgm) 50 300 = 9, =7 (4-— 43 can 050 C\€or\3 {\Y pf.\\ 371% \m an\)~\?—3 \1’ xi“ *2- sm"\‘ 50 ‘thv £35: XCKOU\ 33% ’ U‘Atdn Mei-U4 m “L Con~fifl\fi\.\hv\ \3 £13 ~ 073 (brown l\(\r9.. f— 300% 10. b) Find the escape velocity for the planet. To find the escape velocity we need to determine how large vim needs to be in order to ' e l t' —> ‘ . W ' giv us a so u ion as 7" 00 : rleguue NOT 9 2 7" + “amt — 29R > 0 REQ‘D. so 2 R2 vim > 293 - g > 29R for all 1‘ 1. \/ Thus the escape velocity is vim = «29?. {Cogulvmblfim [ Joe and Dave sit down for coffee. Joe immediately adds cream to his coffee but ave adds cream to his coffee 5 minutes later. At this time, who has the hotter coffee? First we remark that we are ignoring chemistry in this solution. . . d'I‘ __ _ = ~ i We again recall Gui-W that the solution to “J — k(T TA), T(0) To is} Cause, goofing” , T = (To — TA)?! + TA slam/J ’l’LilS. Let the volume of the coffee be M and the volume of the cream be N , Thus when Joe adds cream the initial temperature of the coffee will be reduce to MTo-l-NTC M+N where TC is the temperature of the cream. Therefore after 5 minutes, Joe coffee will have temperature On, exams, of __ MTo-l-NTC -51: T1—( M+N TA)8 +TA Dave adds cream to his coffee after 5 minutes so the temperature of his coffee will be T_MKn—nwhnfl+N% 2— M+N Subtracting the equations we get NTcé5" — NTAéS" + NTA — NTC M + N N(TA — TC) =_____1_$k M+N( 6) ”MW . - . . /\ Since e""‘ < 1 and TA > To (as we are assuming that the coffee 18 than room temperature and the cream is colder than room temperature) we see that T1 — T2 > 0. Hence Joe’s coffee will be warmer than Dave’s. T1—T2= COMMenl’I Tie inla‘ilwe explamlmn is +ha+ 'llne, hoi‘, (mammal milk Cools van! ofiuicldj in'i'l-iallj, dissi‘fza‘l'ms heml- M‘fo 4kg air, OK 41m ol'lux howl, Malena 4h Cream— im'Mzdia-lelj means +kocf Mucln 0“ 4lrfis (New: We is atrorteA by 4M “den/hi5 “‘5‘“ Ml lOE‘l’er he“ 3*”de cream. “for 43) Sl‘vxcz Tl rum auecf' Shefiifljv i: ...
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