Homework 7 - Mark Biagi Homework #7 Activity 16-8 A. The...

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Mark Biagi Homework #7 Activity 16-8 A. The number of essays required for a confidence interval of 99% is .01=2.576(square root of (.15)(.85)/n. Solving for the equation n = 8461. B. Two ways to accomplish this would be to use a lower confidence interval of say 90%. You could also use a wider margin of error of .03. Activity 16-12 A. The margin of error is 100%-95%=5%/2=2.5%. B. The confidence interval is (74.87, 77.13). This interval means that 95% of samples will have a mean between 74.87% and 77.13%. C. The study did use a random sample size which satisfies the first rule. Since n pos greater than 10 and n(1-P) is also greater than 10, the technical conditions are satisfied. Activity 16-14 A. A 95% confidence interval for the proportion is .54 plus or minus (1.96) x square root of . 54(.66)/1208 = .5554 plus or minus (1.96)(0.1434) = .54 plus or minus 0.281 = (.512, .568). B. Yes, since all of the numbers in the interval are bigger than 50 it suggests that more than half of viewers supported Santos. Activity 16-17 A. The proportion of simulated repetitions that resulted in no mother getting the correct baby was 358/1000 = .358. B. For a 95% CI, you calculate .358 plus or minus 1.96 times the square root of . 358(1-.642)/1000= .358 plus or minus (1.96)(.015) - (.355, .361). C. You are 95% confident the long-term proportion of times that no mother would get the correct baby is between .355 and .361.
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D. π = 3.75 E. Yes, the 95% confidence interval succeeds in capturing the population parameter. F. If 1000 different statistics classes carried out this simulation, you would expect roughly 95% or 950 of their intervals to succeed in capturing π = .375, whereas you would expect about 50 of these intervals not to contain .375. G. For an 80% CI, you calculate, .359 plus or minus (1.282)(.01517) = .359 plus or minus . 0194 = (.34, .38). Yes, this interval just succeeds in capturing π =.375. If 1000 different statistics classes carried out this simulation, you would expect roughly 80% or 800 of their intervals to succeed in capturing π = .375, whereas you would expect about 200 of these intervals not to contain .375. Activity 17-6 A . You would reject the null hypothesis at the a = .10 level because the p- value is less than .05 and therefore less than .10. B . You do not have enough information to know whether you would reject the null hypothesis at the a = .01 level. Although you know the p -value is less than .05, you do not know whether it is less than .01. C . You know that you would fail to reject the null hypothesis at the a = .03 level because you know the p- value is greater than .05 and therefore greater than .03. D . You do not have enough information to know whether you would reject the null hypothesis at the a = .07 level. Although you know the p -value is greater than .05, you do not know whether it is greater than .07. Activity 17-7
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This note was uploaded on 05/23/2010 for the course MATH 153 taught by Professor Garant during the Spring '10 term at Prairie State College .

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Homework 7 - Mark Biagi Homework #7 Activity 16-8 A. The...

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