Homework 9 - MarkBiagi Homework#9 Activity2111

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From Summary Statistics Difference of Proportions Attribute (categorical): unassigned Attribute (categorical or grouping): unassigned Interval estimate of the difference in proportions 663 out of 1036 , or 0.639961 , FirstAttribute are Category . 717 out of 996 , or 0.71988 , SecondAttribute are Category . Confidence level: 99.0 % Estimate: -0.0799181 +/- 0.0530938 Range: -0.133012 to -0.0268243 Mark Biagi Homework #9 Activity 21-11 A. It represents the difference in population proportion of girls who have televisions in their room  and the population proportion of boys who have a television in their room. B. To calculate this interval we do (.64-.72) plus or minus 1.96(square root 2.22E-4 + 2.02E-4) =  -0.8 plus/minus (1.96)(0.0206)  (-.1204, -.0396) You are 95% confident that the proportion of all girls who have televisions in their bedrooms is  somewhere between .0396 and .1204, less than the proportion of all boys who have televisions  in their bedrooms. The fact that all the values in your confidence interval are negative indicates  that the population proportion of girls is strictly less than the population proportion of boys. C.    The midpoint of both intervals is the same (.64 -.72 =.08). The 99% confidence interval is wider  than the 95% confidence interval. Activity 21-19
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From Summary Statistics Compare Proportions Attribute (categorical): unassigned Attribute (categorical or grouping): unassigned Ho: Population proportion of makes in conventional equals that of makes in underhand Ha: Population proportion of makes in conventional is not equal to that of makes in underhand 63 out of 100 , or 0.63 , in conventional are makes 78 out of 100 , or 0.78 , in underhand are makes z : -2.326 P-value: 0.02 From Summary Statistics Compare Proportions Attribute (categorical): unassigned Attribute (categorical or grouping): unassigned Ho: Population proportion of makes in conventional equals that of makes in underhand Ha: Population proportion of makes in conventional is not equal to that of makes in underhand 315 out of 500 , or 0.63 , in conventional are makes 390 out of 500 , or 0.78 , in underhand are makes z : -5.201 P-value: < 0.0001 a.  The null hypothesis is that Reilly’s probability of successes is the same with both methods of  shooting free throws. In symbols, H 0 :  π  underhand =  π conventional . The alternative  hypothesis is that Reilly’s probability of successes is greater with the underhand method than  with the conventional method. In symbols, H a :    π underhand <  π conventional .
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This note was uploaded on 05/23/2010 for the course MATH 153 taught by Professor Garant during the Spring '10 term at Prairie State College .

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Homework 9 - MarkBiagi Homework#9 Activity2111

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