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# Quiz6s - x dx Solution Calling u = 1 cos x we have du =-sin...

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MATH 1501 Quiz 5 October 19, 2009 No books or notes allowed. No laptop, graphic calculator or wireless devices allowed. Write clearly. Name:

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MATH 1501 Quiz 5 October 19, 2009 1. (10 points) Compute the following definite integral: Z π 2 0 sin( x )
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Unformatted text preview: x ) dx. Solution: Calling u = 1 + cos( x ) we have du =-sin( x ) dx so that Z π 2 sin( x ) p 1 + cos( x ) dx =-Z 1 2 √ udu = Z 2 1 √ udu = 2 3 u 3 2 ﬂ ﬂ ﬂ 2 1 = 2 3 ‡ √ 2-1 · Page 1 of 1...
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Quiz6s - x dx Solution Calling u = 1 cos x we have du =-sin...

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