hw2 - v = 12 t i + 36 t 2 j-3 t 2 k m / s The acceleration...

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TAM212 Introductory Dynamics Spring 2005 S. Balachandar Homework 2 (1.8, 1.18) 1.8 The displacement vector is given by L = 50 ˆ i + 60ln t ˆ j kg · m / s The rate of change is calculated by simply Fnding the derivative with respect to time dL dt = 60 t ˆ j kg · m / s 2 The value, at t = 3 s , is found by substituting in above equation dL dt ± ± ± ± t = 3 = 20 ˆ j kg · m / s 2 1.18 The velocity vector is given as
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Unformatted text preview: v = 12 t i + 36 t 2 j-3 t 2 k m / s The acceleration is the rate of change of velocity and hence a = dv dt = 12 i-72 t 3 j-6 t k m / s 2 Substitute t = 2 s to Fnd the acceleration at that time a | t = 2 = 12 i-72 2 3 j-6(2) k m / s 2 = 12 i-9 j-12 k m / s 2...
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This note was uploaded on 05/24/2010 for the course TM 212 taught by Professor Richard during the Spring '10 term at University of Illinois, Urbana Champaign.

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