{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

hw3 - TAM212 Introductory Dynamics Spring 2005 S...

Info icon This preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
TAM212 Introductory Dynamics Spring 2005 S. Balachandar Homework 3 (1.36, 1.43) Ensure that the units are consistent across the equations you use. If the problem states usage of British Units, make use of British Units consistently throughout your solution. Similarly for SI Units. Make sure that the units match for the left and right hand side of the equations, and also for all the terms within an equation. Be especially aware of miles per hour to feet per second kind of usage. 1.36 The velocity is given by v ( t ) = 35cos π t 40 m / s To find the position of the point, we integrate it x ( t ) = Z v ( t ) dt = Z 35cos π t 40 dt = 1400 π sin π t 40 + C where C is the integration constant To find the integration constant, we make use of the fact that x = 10 m at t = 0. Substituting that in the above equation x (0) = 10 sin π 0 40 + C = 10 C = 10 So, the position of the point at any given time t is given by x ( t ) = 10 + 1400 π sin π t 40 To find the aceleration, we need to differentiate velocity with respect to time v ( t ) = da ( t ) dt = d ( 35cos π t 40 ) dt = - 7 π 8 sin π t 40
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Now we can plot the curves for the velocity and acceleration 0 50 100 150 200 250 300 350 400 450 500 0 5 10 15 20 25 30 position (x) time (t) x(t) -3 -2.5 -2 -1.5 -1 -0.5 0 0 5 10 15 20 25 30 acceleration (a) time (t)
Image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern