{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

hw3 - TAM212 Introductory Dynamics Spring 2005 S...

This preview shows pages 1–3. Sign up to view the full content.

TAM212 Introductory Dynamics Spring 2005 S. Balachandar Homework 3 (1.36, 1.43) Ensure that the units are consistent across the equations you use. If the problem states usage of British Units, make use of British Units consistently throughout your solution. Similarly for SI Units. Make sure that the units match for the left and right hand side of the equations, and also for all the terms within an equation. Be especially aware of miles per hour to feet per second kind of usage. 1.36 The velocity is given by v ( t ) = 35cos π t 40 m / s To find the position of the point, we integrate it x ( t ) = Z v ( t ) dt = Z 35cos π t 40 dt = 1400 π sin π t 40 + C where C is the integration constant To find the integration constant, we make use of the fact that x = 10 m at t = 0. Substituting that in the above equation x (0) = 10 sin π 0 40 + C = 10 C = 10 So, the position of the point at any given time t is given by x ( t ) = 10 + 1400 π sin π t 40 To find the aceleration, we need to differentiate velocity with respect to time v ( t ) = da ( t ) dt = d ( 35cos π t 40 ) dt = - 7 π 8 sin π t 40

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Now we can plot the curves for the velocity and acceleration 0 50 100 150 200 250 300 350 400 450 500 0 5 10 15 20 25 30 position (x) time (t) x(t) -3 -2.5 -2 -1.5 -1 -0.5 0 0 5 10 15 20 25 30 acceleration (a) time (t)
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern