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Unformatted text preview: TAM212 Introductory Dynamics Spring 2005 S. Balachandar Homework 3 (1.36, 1.43) Ensure that the units are consistent across the equations you use. If the problem states usage of British Units, make use of British Units consistently throughout your solution. Similarly for SI Units. Make sure that the units match for the left and right hand side of the equations, and also for all the terms within an equation. Be especially aware of miles per hour to feet per second kind of usage. 1.36 The velocity is given by v ( t ) = 35cos t 40 m / s To find the position of the point, we integrate it x ( t ) = Z v ( t ) dt = Z 35cos t 40 dt = 1400 sin t 40 + C where C is the integration constant To find the integration constant, we make use of the fact that x = 10 m at t = 0. Substituting that in the above equation x (0) = 10 sin 40 + C = 10 C = 10 So, the position of the point at any given time t is given by x ( t ) = 10 + 1400 sin t 40 To find the aceleration, we need to differentiate velocity with respect to time...
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This note was uploaded on 05/24/2010 for the course TM 212 taught by Professor Richard during the Spring '10 term at University of Illinois, Urbana Champaign.
- Spring '10