# Hw25 - =-960 ˆ j α β 2 ˆ k ×-12 13 ˆ i-5 13 ˆ j a A ˆ i =-960 ˆ j-12 13 α β 2 ˆ j 5 13 α β 2 ˆ i Equating the ˆ i and ˆ j

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TAM212 Introductory Dynamics Spring 2005 S. Balachandar Homework 25 (3.121, 3.124) 3.121 A B C β 1 β 2 β 3 v C = 20 ˆ i f t / sec v C = ω β 3 × r I ± C 20 = 5 12 ω β 3 ω β 3 = 48 rad / sec ω β 3 = - 48 ˆ k rad / sec v B = ω β 3 × r I ± B = - 48 ˆ k × 10 12 ˆ j = 40 ˆ i f t / sec At the position indicated, v A and v B both have velocities parallel to each other and so the angular velocity for the bar β 2 is zero. ω β 2 = 0 v A = v B = 40 f t / sec Acceleration of B, a B = ± ± > 0 a C + ± ± > 0 α β 3 ˆ k × r CB - ω 2 β 3 r CB = - (48) 2 5 12 ˆ j = - 960 ˆ j f t / sec 2 1

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Acceleration of C, a A = a B + α β 2 ˆ k × r BA - ± ± > 0 ω 2 β 2 r BA

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Unformatted text preview: =-960 ˆ j + α β 2 ˆ k × (-12 13 ˆ i-5 13 ˆ j ) a A ˆ i =-960 ˆ j-12 13 α β 2 ˆ j + 5 13 α β 2 ˆ i Equating the ˆ i and ˆ j components separately, =-960 ˆ j-12 13 α β 2 ˆ j α β 2 =-1040 rad / sec 2 a A = 5 13 α β 2 a A = 5 13 (-1040) a A =-400 f t / sec 2 a A =-400 ˆ i f t / sec 2 2...
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## This note was uploaded on 05/24/2010 for the course TM 212 taught by Professor Richard during the Spring '10 term at University of Illinois, Urbana Champaign.

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Hw25 - =-960 ˆ j α β 2 ˆ k ×-12 13 ˆ i-5 13 ˆ j a A ˆ i =-960 ˆ j-12 13 α β 2 ˆ j 5 13 α β 2 ˆ i Equating the ˆ i and ˆ j

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