hw33 - 2 P y-60 = T √ 2 P y = 60 M c = 0(only translation...

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TAM212 Introductory Dynamics Spring 2005 S. Balachandar Homework 33 (4.1, 4.8) 4.1 4 3 C P N mg O For the bar to translate (without any angular rotation), M c = 0 P r OC x - N r OC y = 0 P ± 4 5 ²± l 2 ² - N ± 3 5 ²± l 2 ² = 0 P = 3 4 N P = 3 4 mg 1
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4.8 A C P x P y T B D 60 lbs Forces and moment acting on the bar: F x = ma x T cos45 + P x = 60 32 . 2 32 . 2 T 2 + P x = 60 F y = ma y T sin45 + P y - mg = 0 T
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Unformatted text preview: 2 + P y-60 = T √ 2 + P y = 60 M c = 0 (only translation) T cos45(3)-P x (3) = T √ 2-P x = Solving the three equations, we get T = 42 . 4264 lb P x = P y = 30 lb P = 30 ˆ i + 30 ˆ j lb 2...
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hw33 - 2 P y-60 = T √ 2 P y = 60 M c = 0(only translation...

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