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E234-S09-S-exam 1 - E234THERMODYNAMICS Exam1February9,2009...

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Stevens Institute of Technology E234 THERMODYNAMICS Exam 1 – February 9, 2009  105 points total; Maximum grade is 100   Data: water  = 1000 kg/m 3       oil  = 0.9 g/cm 3       mustard  = 1.1 kg/liter  g = 9.81 m/s 2 k plaster  = 0.79 W/m.K k insulation  = 0.037 W/m.K k brick  = 0.7 W/m.K 1. 20  A 2-liter container is filled with 500 g of olive oil, 300 g of vinegar and 100 cm 3  of  mustard. Find the average specific volume and density of the masses when you exclude the  mass and volume of the air. Assume vinegar has the same density as water. Average specific volume in SI units: Average density in g/cm 3  and kg/m 3 : V = m oil / oil  + m vin / vin  + V mustard  = 500/0.9 + 300/1 + 100 = 955 cm3 m = m oil  + m vin  + V mustard mustard  = 500 + 300 + 100x1.1 = 910 g  v = 0.955/0.910 = 1.049 L/kg = 1.049x10 -3  m 3 /kg    v  kg/m 3 2.
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  • Spring '09
  • GALLOIS
  • total average power, average specific volume, Technology E234 THERMODYNAMICS, air. Assume vinegar, base metabolic rate, cm water =gh

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