lab_solution2

lab_solution2 - ECE 101 Fall 2009 Lab#2 Solutions Results...

This preview shows pages 1–4. Sign up to view the full content.

ECE 101 - Fall 2009 Lab #2 Solutions Results: Problem 2.10 (a) – y[n] = x[n] + α x [n – N] To find the impulse response, find the response when x[n] = δ [n] Therefore, h[n] = δ [n] + 0.5 δ [n – 1000] Problem 2.10 (b) – y[n] = x[n] + α x[n – N] (2.21) z[n] + α z [n – N] = y[n] (2.22) Overall Difference Equation: z[n] + α z [n – N] = x[n] + α x[n – N] => Eq. (2.22) is an inverse of Eq. (2.21) z[n] = x[n] is a valid solution to the overall difference equation. Problem 2.10 (e) – The result, hoa has an abnormality spike because it contains only 5000 terms due to her only being a sample approximation defined to 4001 terms when in actual fact it should be an infinite length impulse response signal.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

Page1 / 4

lab_solution2 - ECE 101 Fall 2009 Lab#2 Solutions Results...

This preview shows document pages 1 - 4. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online