lab_solution2

lab_solution2 - ECE 101 - Fall 2009 Lab #2 Solutions...

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ECE 101 - Fall 2009 Lab #2 Solutions Results: Problem 2.10 (a) – y[n] = x[n] + α x [n – N] To find the impulse response, find the response when x[n] = δ [n] Therefore, h[n] = δ [n] + 0.5 δ [n – 1000] Problem 2.10 (b) – y[n] = x[n] + α x[n – N] (2.21) z[n] + α z [n – N] = y[n] (2.22) Overall Difference Equation: z[n] + α z [n – N] = x[n] + α x[n – N] => Eq. (2.22) is an inverse of Eq. (2.21) z[n] = x[n] is a valid solution to the overall difference equation. Problem 2.10 (e) – The result, hoa has an abnormality spike because it contains only 5000 terms due to her only being a sample approximation defined to 4001 terms when in actual fact it should be an infinite length impulse response signal.
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lab_solution2 - ECE 101 - Fall 2009 Lab #2 Solutions...

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