solution1_supplement

solution1_supplement - = 3 cos(4 t π 3 is periodic with T...

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ECE 101 – Linear Systems Fundamentals, Fall 2009 Supplemental Problem Set #1 Solutions (send comments/questions to [email protected]) 1.21 (c),(f) Plots: 1.22 (b) Plot: (e) u[3–n] is 1 for n 3, and 0 for n > 3. So, multiplying by u[3–n] keeps the values of x[n] for n 3. Since x[n] is non-zero only for –4 n 3, all of x[n] is retained: x[n]u[3–n] = x[n] . 1
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1.23 (a) (c) 1.24 (a) 2
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(b) 1.25 (a) x ( t
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Unformatted text preview: ) = 3 cos(4 t + π 3 ) is periodic with T = 2 π/ω = 2 π/ 4 = π/ 2. (d) x ( t ) = Ev { cos(4 πt ) u ( t ) } = 1 2 cos(4 πt ) ⇒ x ( t ) is periodic with T = 2 π/ω = 2 π/ 4 π = 1 2 . 1.26 (a) x [ n ] = sin( 6 π 7 n + 1) is periodic with T = 7. (e) x [ n ] = 2 cos( π 4 n ) + sin( π 8 n )-2 cos( π 2 n + π 6 ) is periodic with T = 16. 3...
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solution1_supplement - = 3 cos(4 t π 3 is periodic with T...

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