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Unformatted text preview: MAE140 - Linear Circuits - Fall 09 Midterm, November 10 Instructions (i) This exam is open book. You may use whatever written materials you choose, including your class notes and textbook. You may use a hand calculator with no communication capabilities (ii) You have 70 minutes (iii) Do not forget to write your name, student number, and instructor B +- 10 V 0.5 A 10 40 20 10 Ω Ω Ω Ω A (a) Question 1. A v S i S B D C R 2 R 4 R 3 R 1 i 1 i 2 (b) Question 2. Figure 1: Circuits for questions 1 and 2. 1. Equivalente Circuits Part I [4 points] Use source transformations and association of resistors to find the Thevenin equiva- lent to the circuit in Fig. 1(a) as seen from terminals A and B. Part II [4 points] A classmate was arguing with you that one would “extract” the most power out of this circuit by connecting a very small resistance between terminals A and B. You argued that he/she was wrong and that a 20 Ω resistor would be a better choice. Who is right and why? Hint #1: Don’t complicate: all you need to do is compare the two options! Hint #2: Use the Thevenin equivalent computed in Part I to answer the question. Solution: Part I: A possible series of source transformations is shown here: 10 V +- +- 10 V 40 20 Ω Ω A B 20 Ω (+ 1 point) 20 V +- 40 40 Ω Ω A B Ω 40 Ω A B 0.5 A 40 (+ 1 point) 0.5 A 20 Ω A B (+ 1 point) Ω +- A B 10 V 20 (+ 1 point) Part II: Let’s investigate the two scenarios. In the case of a small resistance, say R = Ω , using the Thevenin equivalent and voltage division we have that...
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- Spring '09
- Thévenin's theorem, Voltage source, R Vin R