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Population+genetics+KEY WI2010

# Population+genetics+KEY WI2010 - Population Genetics...

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Population Genetics Problem Set BIO 171 W2010 Problem 1. a. frequency of A is 0.5 A, frequency of a is 0.5 a b. i. egg with A = 0.5 b. ii. sperm with A = 0.5 b. iii. egg with a = 0.5 b. iv. sperm with a = 0.5 c. Egg and sperm genotypes are A and a (in equal frequencies) - set up Punnett Square below: A a AA Aa aA aa Genotype frequency of AA = 0.5 x 0.5 = 0.25 Genotype frequency of Aa = 0.5 x 0.5 = 0.25 Genotype frequency of aA = 0.5 x 0.5 = 0.25 Genotype frequency of aa = 0.5 x 0.5 = 0.25 Problem 2. a. If HWE assumptions are met ( i.e., no selection, no genetic drift, no gene flow, no mutation and random mating with respect to gene under study), the Hardy Weinberg principle PREDICTS that genotype and allele frequencies will not change from one generation to the next generation. b. i. If you sample just after the major weather disaster, then HWE equilibrium cannot be assumed , as genetic drift likely impacted allele frequencies when population size was reduced from very large (given in problem 1) to large (given in problem 2). b. ii. After one generation of random mating with respect to gene under study and no evolutionary processes acting on this gene , then you would be able to use Hardy Weinberg

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Population+genetics+KEY WI2010 - Population Genetics...

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