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Unformatted text preview: (2) α = 1 + [I]/K I K I = 10 mM/2.88 = 3.5 mM We could also determine KI’, the inhibition constant for inhibitor interaction with ES complex. This should be equal to the KI that was determined above. Calculate the α ' from the inhibitor curve, using the yintercept (instead of the slope). yintercept inhibitor = α / Vmax 0.3 = α ’ / 11.1 μ M/s α ' = 3.33 Calculate K I ’ from α α ’ = 1 + [I]/KI’ K I ’ = 10 mM/2.33 = 4.3 mM Note: Notice that the KI values are not apparently the same. This comes from the fact that I drew onto the graph lines extrapolated from the line created from the data points through the x and y axis. These lines are somewhat askew and give extrapolated points that are off a bit from the true extrapolated lines. In other words, I didn’t draw the extrapolated lines very well. The KI values, for all intents and purposes, the same....
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 Fall '08
 drpernecky
 Chemistry, Enzyme, Reaction, Enzyme inhibitor, noncompetitive inhibitor, ki, inhibitor curve

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