hw6_2.39_2.45

# hw6_2.39_2.45 - problem 245 2.45 Links BC and DE are both...

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Unformatted text preview: problem 245 2.45 Links BC and DE are both made ofstee1(E= 29 x 106 psi) and are i in. wide and i in. thick. Determine (a) the force in each link when a GOO-lb force P is applied to the rigid member AF shown, (b) the corresponding deﬂection of point A. (200 ii: — gmgc wé9§(§}+ ﬁﬁvﬁg ESQ FEE: ZFﬁg—Z‘pr‘p ‘ Problem 2_ 39 2.39 Three steel rods (E = 200 GPa) support a 36'-kN load P, Each ofthe rods AB and CD has a ZOO—mm2 cross-sectional area and rod EF has a 625-mm2 cross-sectional area; Neglectingthe deformation of rod BED, detelmine (a) the change :in length of rod EF,’(b)1h'e*s11ess:in:eachrod‘. Use membaw BED a6 a. ~Hee £0417. PM? > \$305» 8)] symme/‘fveb ow b7 ZME :0 R0 = PAB- 948+ En +PEF " P :0 7: ‘4" 2 Fﬁg '7' pEF 8 : ....... : PancE S : PEP LEF A8 EAA-Q ' ' E Am ’ EF' . EAEF S;V1C€ LA‘B ": QANA ‘AAE 1‘ ACD‘) 5,375 : 5CD ﬁ —— .‘Mnce Par‘n‘f‘: ‘ I 'bj-qv‘tz Jake's?) SB : \$.45) SD = 5c}: g-S’E‘ :‘ 55F SE : ~S‘G- 1-” 3:, - = Age 122 _,, zoo . m . as A5; L'AvTS PEP d 625 ‘500? 735‘ , , = 0.2% Pa: ' 2 F1“ PE; .—- (25(04543139 4.123: 145:9. P9 ___E_ _ M - As . PEP ‘ 1.5/1 ‘ LEIQ _' 23‘3“) “O -N“ ~. as = Pa, = (o.25:e)(23.8;oxzoaj r 6.0?5’wlo-a N ~ g e (233/03’10‘M4'ooMo‘s? S 35;- ~ mg M -= ’76. 2 >110 m ‘ ,Zadxto ‘7 ) ( @253: I o" V ; . ( ‘) I = 0.0 76 2 MM “a "rev 8 _ ‘5 _ (aoayxioaﬂébowo‘sj ~ , . — ‘8 M ‘ (Zooxlo‘)C1oogx£O-s‘} : 75.90410 'm ' 3 0‘5 6A3 : '51.), = :‘B =- ‘W = 30-5X10‘pd= (30.5'HPa-aa ~ AB _ PER. _.:23;810x103._ _ . c » _ , - 55,» v—Aep ~-'W - ‘33.} X10» 11%,- 38., MPa. ...
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