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Unformatted text preview: wuwsmmm Problem 3.35 3.35 The electric motor exerts a 500 N  m torque on the alurm'num shaﬁ ABCD
when it is rotating at a constant speed. Knowmg that G =.27 GPa and that the
torques exerted on pulleys B and C are as shown, determme the angle of mm between (a) B and C, (b) B and D 200 Nu. (CL) Angle ﬁtwfst between 8233! . T8c=tzoo New) Lu: LZM
Créd = 00mm} G— = 27X/Oa Po. 300Nm a; l£c"= strenuo" m l  (mum " _3 , ..
CPB/c GJ' vWWT)‘ ”24.57on mm! £98k; 1.38% «a 1% Us) An ﬂe o‘F +VES+ he'l‘weew B “J 13..
H‘ Ta, :500 NmJ LCD=03,“ C=%J=0.024mj G=27¥/0"Pq
J; 316" = %Z(002+l"= 52.1.153Ylo'7 w,” ' C? = (500M033 ' ‘ (PB/p : @8/4" Goa/D = 29357x/0—34 3L7SO>¢[O‘% :: 56‘137y/0‘3W‘J _
Cpapa: 1 3.220 Q : 3]?8OXIO'3 my .800N~m Problem 3.36 13.36 The torques shown are exerted on pulleys A, B, and C. Knowing that both shafts are solid and made of brass (G = 39 GPa), determine the angle of twist v _ 40 mm
between (a) A and B, (b) A and C. 1200 N ‘ m (as A 19. °¥+w.'s1‘ 5611mm ml 13  400mm /
TAB 2 [+00 Him.) LAB: L2 M . . I . .
C =ilfo": O;C>!Sm G: 373/0731 «35%[cqr 79.52 we“ m 63 (3? >‘t '0“ l (79. 52x 10“?) t _
= 0.154772 W! 9 90M; _— 5127" f) 4: (b5 Angie OP, $013+ Between A 4AA) C ,
T3: = 800 N~m J Lu: [.8 m) <: 4:! =o.~ozo "H G = sex/0‘91 T “I 
JM=§6 = $101020) r 25:.327uo" m” _ (gowns) ‘
R z
‘98]; (39¥107)(25l.327xlo'7) 0. mean) 2 (pm TL  (L100)(I.Zl —___________
Fromm"151 lﬂmnlﬂcﬂhdasﬂmxmbmdadhﬁhrulndmﬂchdm
mmdgmlﬁ thhm' ofn‘pdm" iﬂJxlﬂ‘paiﬁzt
3: pi _ damnmm mm]
hwlinduﬂmilicyﬂuulc mm EM); =12.5—TA —TC :0 TA
12.5 Kip.in TAB = TA
U as TA Tc THC = 7;, —12.5
12.5 Kip.in TB C ( 2) Geometric compatibility: A¢AC = 0 = A¢AB + A¢BC
TL (3)A¢ = a Combining (2) and (3) we get,
= TAx12 + (TA —12.5)x(18)
3.7x106 xzx1.54 /32 5.6x106x7rx2.04 /32
TA = 2.9841Kip.in = TAB,
TBC = 2.9841 —12.5 = —9.516Ktp.in ”Meow “1.54/32 “2.04/32— ...
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 Spring '10
 Jenkins

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