hw25_7.38_7.71

# hw25_7.38_7.71 - Problem 7,38 1.38 Solve Prob 7.16 using...

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Unformatted text preview: Problem 7,38 1.38 Solve Prob. 7.16, using Mohr’s circle: IRWIN Fmﬂmgivmsmofmmﬂnmmmdﬂuﬁng messes mulhzelcrmdmnimbemmch(a)ﬁ° clockwise,(b) l0° Woekwise. 'Epuftlal Pm‘nis ﬂ tlnht‘; :[n&. X: (°,'S hi) Y: (s kai, 5m) CI Hksi, o) (a) e = 25“}! 29:50“ 1 5p: 5:.34°-50' 1.34“ 6'," -’ 6...¢ - Recs? = -2.-'-lo I45; 4 2:3. - Rang) .- 0.15'ks.‘ - 63- = 6m + 1?“an = Ivo ks; -- (b) e= no“), 29= 20') (P = 5".3‘f°+ 20° :' 71.3‘F' 5'" '-' 5‘... - R an? -'-' I.‘?5- Its; 1-? -_ R sin 9 = 6.07 3:3; ‘ 6:,- '-' 6'... + Quad]? = 8.05.; kSI' Problem 7,71 7.70 and 7.71 For the state of stress shown, determine the maxunum shealing stress when (a)u,=+ 24 Ml’a,(l>)cr,z = — 24MPa,(c) a,= 0. sz-MMPa.) 6'1:- Ilr'vtPa.J 152—3; “PA 6;: 61.32.- came 61‘ szfgbk‘: - llMF’q (a) 6’3: +2H MPa 61: c5 MPa 61 = ~12 MR: GM: 6; MPa 6% = — nMPI. rm: 45 (6;, '6‘...-..\ = 3r, Mp,t 4 CE) 2: —2t{ HPq. Ga - eeMPe, 6]," -— [2 MP; 6;“: cs MPa 61,-, = -24 MP4 1.1: 1(6‘.'_...-6‘_.-.\= ‘iS’MPq, 4 (c) 6;.- ee MPG, 65; = ~12 MPa. 6W2 66m 6L5 — :2 “Ha w=%C6m.-6:.-A = 3‘! H96» “ Proprietary Material. 0 2009 The Mcan-l-[ill Companies, Inc. All rim mewed. No part ofthis Manual may be displayed, reproduced, or distributed in any farm or by any means, without the print written permission uftlle publisher, ur used beyond the limited distribution to watchers and educamrs permitted by McGraw-Hill ﬁn their individual course preparation. A etudem using this manual is using it without permission. ...
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