ee110_spring07_solutions

ee110_spring07_solutions - EE110 07S Mid-Term 1 Name LAST...

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Unformatted text preview: EE110 07S Mid-Term 1 Name LAST Student ID 1. (10 points) Mark all of the choices that are true: In an inductive circuit, a) Current leads voltage b) Voltage leads current c) Current lags voltage d) None of the above SOLUTION e) All of the above FIRST EE110 07S Mid-Term 1 Name | Student ID 2. (36 points) Ifym = 50.0“ and 1m 2 40.120“, find the complex power 5 associated with (either provided by or absorbed by) block B. SOLUTION By the Passive Sign Convention, from the standpwht afbox 8, a negative Sign mat be used in the V-I calculation. 5 = £3» 1; : _%(5040°)(404 ~ 120°): -1000; —120° S 2 500+ j866 Midterm 1 BE] 10 Problem 3 Solution Find the Thevenin Equivalent looking into terminals 3 and b Zth = (3a j100)+ (—j2.4// 1200) 2112 = 7-97 + j0.639 — 12.43 Zth = 7.97 — j1.79 Zth = 8171—12156" 11(3 + j100)- slioi = 0 11 = ~0.0493 — j0.00398 12(j200 — J12.4) + SliO" = o 12 = 0.0253 Vflm '= 110100) V3200 = 120200) Wk 2 V1100 +Vj290 Vth = 0.398 + 10.08 = 0.406'1136 ...
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