20102ee161_1_HW1_solution

20102ee161_1_HW1_solution - (A/m Problem 7.9 Solution First...

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Problem 7.9 Solution: First convert to time domain expression { } { } { } ) 6 / sin( 30 ˆ ) 6 / cos( 30 ˆ 30 ) ˆ ˆ ( Re 30 ) ˆ ˆ ( Re ~ Re ) , ( 6 / 2 / 6 / z t y z t x e e e y x e e y j x e E t z E t j z j j t j z j t j π ω = + = + = = r The modulus is ( ) ) / ( 30 2 / 1 2 2 m V E E E y x = + = r Also s rad k z t E E x y / 10 5 10 3 6 / ) 6 / ( ) ( tan 7 8 1 × = × = = = = µε ψ The direction is = = = = × = = = ns t at ns t at t at t t z At o 10
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This note was uploaded on 06/01/2010 for the course EE EE161 taught by Professor Wang during the Spring '09 term at UCLA.

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20102ee161_1_HW1_solution - (A/m Problem 7.9 Solution First...

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