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EE161mt1 - fit I EElfi-l 391mg am...

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Unformatted text preview: fit I ? EElfi-l 391mg am}: Name: 'L’Emmhfi'fl-‘f HIE-J?“ 19:; I Grade: 89' Pmbiem #1 (25 points}. The electric field of a plane wave propagating in airhas the fullnwiugflxprassipn giveIt by E(z,t‘] =.£‘4 mafia)! +.tiz)+ 3333mm?! + fififi points) Find the apex-fling flcqupntzy pfflte wave. {2) (_5 points) Witt: down the phasor exereeeien efthe e1eeeie field. [3} flippiutfij Find the eeeeeieted magnetic: field. (4} (1 U. points) Idtentify the Wave pplarizatiunsstatea with mtation'directions and find the_axi_ai ratio. --u -- ."H' ‘1 ' - Jr _ = E {2,13 : “a“: lame (wt—Mei) +3 .‘ MEL“) WEB? L‘ (- ___,__ $itmé:\f—L|;E\* fl 13;“); Ih'flflr-I-EE "' E.) —, _ p r. w _-. P “(Ir—- e £1 4’“_ E: ._ :15: _ ”wéiéle ijlUE I._ _ - I 1w“..- PT __ I. -L ‘ o . 3. e - e, ““t 5 Ewe—wear Iemt be? e__ __ _ I, '53" — v "' E- r c .5 -.I_ _ III-EF‘ 1 lb} A. u' 1: a N f r “5+- 4 :3. PIIL'. é —. in. it IE "t La ll" [5:3 9: [EJR‘E -: Hi J‘- -Q Q_ ____ _ F r _— __ rt)?“ :- t- ‘t I» L; f“ 1' EA EL w ‘6‘) t:- . 4 (“J - g — 11: 2. _ I,“ I -- K :3} E? n,- "u N -_I ._ 54K _ _ . at. 4-11. U '5- E‘ Z hjkuj'gh I'll fixer; "git .fiflgré “3 “I “ tbrtah“ Jetfie,“ a . 5 . ' 135% \‘j l. fi— 0% fl .5: «IE t HI ___: - —.—L,—,L- “Keg— pet: fieeflfi e ) at 1'11] 1 _J. _. _. '51:; K.‘ A ELI“: A L ‘t 7' _ __J—ef— &x‘ "1% E. -‘- ‘L EHRE “J— J —_ :U‘JT it {3% A A. r I t h d “TEE‘M’T?! WM #3: .1 .ge] :1: ”a.“ fe_ .L‘fi‘“ ":3 “LP mag “a" q-Jwao W: _J _ ‘1“: 1': Es kg Drfll E. '1...- “- [MEI - 1'? t "~ ‘1“: to 3 \ x I — f“ I" Leaf 13‘1” + :33 H r' ‘ — "‘_ _""" _'_ if :1 5L ‘ ,3 . e. . .. - a ,l‘e‘ttt} urea wt llt't {£159} 751?; RENO 3‘“ L trail-.718 1': 4. I;%\] _g‘tOJaHHO {Fifi/Q ) II ||_____-‘— __ _ _ _ _ ___ __,_ ___ I xxx/f Problem #2 (25 points) A 25 MHz plane wave propagateE toward positive Z axis. If the wave propagates in a semiconductor material with dielectric constant E = 9 and o": lflfl (Sim). At the reference plane 2:11}, the time domain electric field is measured to he E(U,I}= ilfleosufimt} . Determine (1}{lfi points} the time-domain expression of both the electric field and magnetic field E(z,t)and H{2,1} {2} {5 points) the skin depth of the semi-conductor medium {3} (ID points} the power attenuation in dB scale at Flmm penetration of the medium 'n'.'.l __ "K. I -‘:"'m__ I I. |.'_'-L 'I -I _ _' ? l'fi .j'f fit: I "11:33 I 'In: Were-17%;; L (E'Trxlfiq— Problem #3. [25 pcints)-Tc design the anti-flaring coating cf a glass requires the same type cf coating. is placed in both side cf the glass. If the glass has a dielectric constant cf 4 and the thickness cf the glass can he arhiggg. The light wave incidents on the glass ncmtally. {1) [iii points} Draw the transmission line equivalence to this structure {2) [15 points] If the light wave has a frequencyr cf ll}15 Hz, how shall we select the dielectric constant and the thickness d at" the coating material to make the light pass through the glass huddle-m reflectinn'? ccaflng ah - —F Problem #4 (25 points}. Consider the oblique incidence case of plane wave in air onto a lossless non-magnetic dielectric slab. The dielectric constant is' a}: = 3, and the thickness is unlmoem. Therefore {I} (3 points) for parallel polarization, choose an incident angle so that the wave can pass through the slab Without an}; lees. {2) [12 points} if the fierntenc},r of the wave is 1 GHz, please write down the phase-I: expression of the electric field in both the air and the dielectric slab for parallel polarization [3) [5 points) if the incident were is circularly polarised, how will the axial ratio R change after the wave passes through the slab? inn?" E '3 £306 ...
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