# EC0 - VI3 Assuming the uncertainty in the current I to be...

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John Salek-Raham Physics 152 EC0 Propagation of Errors 1/23/08 VI1 : The unknown resistor was connected to the battery and set so the ammeter current (I) read 30 mA using the 50 mA scale. This was repeated 8 times, and readings from the voltmeter were recorded. Data Table: # Volts 1 4.916 2 4.897 3 4.922 4 4.883 5 4.867 6 4.913 7 4.921 8 4.914 Rm = 167.20 VI2 : Using Microsoft excel, the average voltage (V) was found to be 4.814 volts, with a standard deviation of 0.25 volts. (V = 4.814 + 0.25 volts)

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Unformatted text preview: VI3 : Assuming the uncertainty in the current I to be ¼ of the smallest division of the ammeter: Smallest division of the ammeter = 1.0 mA. Uncertainty in I = 0.25 mA. VI4 : Using equation 6 from the handout, R = V/I, Resistance was found to be (4.814 volts)/(30 mA) = 0.160 This value is about 1000 times smaller than the recorded value of Rm. Using Equation 7: The uncertainty of R = 0.009, VI5 : R = 0.160 + .009 VII : Questions: 1. 2....
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EC0 - VI3 Assuming the uncertainty in the current I to be...

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