Physics M11 - I = MR ^2 2 I = 25043.9 g cm^2 This is close...

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John Salek-Raham Physics 151 Lab M11 11/6/07 V1: Rotational inertia of the disk In this part of the experiment, a steel disk of mass 1254 grams and a radius of 1.23 cm was used to suspend varying weights according to the physics 151 lab manual. Fall time from 90cm was measured. Using the equation : a = 2h T^2 Acceleration was calculated for each mass using the average t for each mass (see attached data sheet). Mt (g) a (m/s^2) 5.9 0. 38 10.9 0. 69 15.9 0. 99 20.9 1.28 25.9 1.61 Acceleration was plotted vs. Mt acceleration vs Mt y = 0.061x + 0.0201 0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 1.8 0 5 10 15 20 25 30 grams m/s^2 a vs. Mt Linear (a vs. Mt)
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Using excel, the slope of this graph was found to be 0.061 g cm^2. Using this slope, and the relationship: I = gr^2 S I = 24305.6 g cm^2 = experimental value (Io) The calculated value of I can be found using the relationship:
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Unformatted text preview: I = MR ^2 2 I = 25043.9 g cm^2 This is close to the experimental value of I. V2: Rotational Inertia of a rod In this experiment a larger falling mass (30.9 grams = Mt’) was suspended from the same apparatus, now with the rod cylinder of 630 grams, and 12.5 x 2.5 cm, from the same height 90 cm. Using the relationship: (see attached data sheet for t values). aR = 2h t^2 aR = 1.43 cm/s^2 Using this value of acceleration, and the relationship: I = m’gr^2 _ Io aR 31299.2 - 24305.6 = 6993.6 g cm^2 Using the equation: Ic = Mr (b^2 + l^2) 12 Ic = 6890.63 g cm^2 This is close to the experimental value, therefore the results are representative of good data collection. VII: Questions : 1....
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