Experiment #02 Finding the Ratio of Moles of Reactants

Experiment #02 Finding the Ratio of Moles of Reactants - 2...

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Experiment 2 Finding the Ratio of Moles of Reactants in a Chemical Reaction Solution A Sodium Hypochlorite, NaClO, 0.050 M "X" in solution Solution B X Potassium Iodide, KI, 0.05 M in NaOH, 0.20 M Solution Ratio Experiment A B 1 0.0 50.0 0.0 2 5.0 45.0 4.2 3 10.0 40.0 8.0 4 20.0 30.0 15.2 5 30.0 20.0 23.2 6 40.0 10.0 32.0 7 42.5 7.5 22.0 8 45.0 5.0 12.5 9 50.0 0.0 0.0 10 50.0 11 50.0 12 50.0 13 50.0 14 50.0 15 50.0 Sodium Thiosulfate, Na
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Unformatted text preview: 2 S 2 O 3 , 0.50 M in NaOH, 0.02 M Sodium Sulfite, Na 2 SO 3 , 0.50 M in NaOH, 0.20 M Change in Temp ( o C) 5 10 15 20 25 30 35 40 45 0.0 5.0 10.0 15.0 20.0 25.0 30.0 35.0 f(x) = -2.87x + 14 R = 0.99 f(x) = 0.79x - 0.02 R = 1 Change in Temp. vs Amount of A Used ml of A used Change in Temp 50 43.11...
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This note was uploaded on 06/02/2010 for the course CHEM 104 taught by Professor Any during the Spring '10 term at UNC Charlotte.

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Experiment #02 Finding the Ratio of Moles of Reactants - 2...

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