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Basic Chemistry (Chapters 1-16)

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CHEMISTRY NAME Problem Set #1 Date Period SOLID-LIQUID PHASE CHANGES 1. In an experiment, 100 grams of water at 80 o C are allowed to interact with ice (at 0 o C). Enough ice is used to cool the water to 0 o C. The ice and water are placed in an insulated container so that all the energy is given up by the water to melt ice at 0 o C, there are 200 grams(ml) of liquid water present. a) According to this data , how much ice is melted? b) According to this data , how much energy is given up by the 100 grams(ml) of water in cooling from 80 o C to 0 o C? (Remember >>>1 calorie/gm/ o C) c) Using the data above determine how much energy is required to melt one grams of ice? d) Explain why the water gets colder. BACKGROUND: In experiment #2 you measured the energy involved in the melting process for water. The results
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Unformatted text preview: expected for the experiment #2 were. H 2 O (solid) + 80 cal/gm ---------> H 2 O (liquid) The energy absorbed during the melting process is used to separate the molecules of the solid and NOT to raise the temperature. 2. A metal spoon, initially at 25 o C, is placed in an insulated cup containing water and crushed ice. After the system has come to thermal equilibrium, there is ice remaining. a) What is the equilibrium temperature of the metal spoon? EXPLAIN! b) What happens to the energy given by the metal spoon? c) If 5.0 grams of ice were melted, how much energy was given up by the spoon? 3. What amount of ice must be added to cool 250 grams(ml) of water at 25 o C to 0 o C and have no ice remaining?...
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PS01.MeltFreeze2001 - expected for the experiment#2 were H...

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