1178864656Xuj

# 1178864656Xuj - Alvarado Patrick Homework 3 Due Feb 8 2007...

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Alvarado, Patrick – Homework 3 – Due: Feb 8 2007, 11:00 pm – Inst: Opyrchal, H 1 This print-out should have 9 questions. Multiple-choice questions may continue on the next column or page – fnd all choices be±ore answering. The due time is Central time. 001 (part 1 o± 1) 10 points A cubic box o± side a , oriented as shown, con- tains an unknown charge. The vertically di- rected electric feld has a uni±orm magnitude E at the top sur±ace and 2 E at the bottom sur±ace. a E 2 E How much charge Q is inside the box? 1. Q encl = ² 0 E a 2 correct 2. Q encl = 2 ² 0 E a 2 3. Q encl = 0 4. Q encl = E ² 0 a 2 5. Q encl = 3 ² 0 E a 2 6. Q encl = 1 2 ² 0 E a 2 7. Q encl = 2 E ² 0 a 2 8. Q encl = 3 E ² 0 a 2 9. Q encl = 6 ² 0 E a 2 10. insu²cient in±ormation Explanation: Electric ³ux through a sur±ace S is, by con- vention, positive ±or electric feld lines going out of the sur±ace S and negative ±or lines going in. Here the sur±ace is a cube and no ³ux goes through the vertical sides. The top receives Φ top = - E a 2 (inward is negative) and the bottom Φ bottom = 2 E a 2 . The total electric ³ux is Φ E = - E a 2 + 2 E a 2 = E a 2 . Using Gauss’s Law, the charge inside the box is Q encl = ² 0 Φ E = ² 0 E a 2 . keywords: 002 (part 1 o± 1) 10 points A point charge o± 6 . 2 μ C is located at the center o± a sphere with a radius o± 11 cm. The Coulomb constant is 8 . 98755 × 10 9 Nm 2 / C 2 , and the acceleration o± grav- ity is 9 . 8 m / s 2 . Determine the electric ³ux through the sur- ±ace o± the sphere. Correct answer: 700234 N

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1178864656Xuj - Alvarado Patrick Homework 3 Due Feb 8 2007...

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