Homework Solutions 12

Homework Solutions 12 - Solutions to Homework #12 (W4150...

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Unformatted text preview: Solutions to Homework #12 (W4150 Intro to Probability and Statistics, S04; special acknowledgements to Aditya V. Prasad) Sec. 11.3. (1) Individual x y 13 29.0 76.7 1 17.3 71.7 14 29.6 78.3 2 19.3 48.3 15 29.9 60.0 3 19.5 88.3 16 29.9 71.7 4 19.7 75.0 17 30.3 85.0 5 22.9 91.7 18 31.3 85.0 6 23.1 100.0 19 36.0 88.3 7 26.4 73.3 20 39.5 100.0 8 26.8 65.0 21 40.4 100.0 9 27.6 75.0 22 44.3 100.0 10 28.1 88.3 23 44.6 91.7 11 28.2 68.3 24 50.4 100.0 12 28.7 96.7 25 55.9 71.7 y = 0.5609x + 64.529 R 2 = 0.1534 0.0 20.0 40.0 60.0 80.0 100.0 120.0 0.0 10.0 20.0 30.0 40.0 50.0 60.0 Arm Strength Dynamic Lift Arm strength vs Dynamic Lift Linear (Arm strength vs Dynamic Lift) a) Using excel, the resulting regression equation is y = 64.529 + 0.5609x . The value of & = 64.529, while value of = 0.5609. b) The point estimate of |30 Y = 64.529 + 0.5609 (30) = 81.356 c) Sec. 11.3. (2) x 77 50 71 72 81 94 96 99 67 y 82 66 78 34 47 85 99 99 68 a) y = 12.062 + 0.7771x ; R 2 = 0.3147 b) |85 Y = 12.062 + 0.7771 (85) = 78.11 Sec. 11.3. (2) 17.3 Residual Plot-30-20-10 10 20 30 0.0 10.0 20.0 30.0 40.0 50.0 60.0 17.3 Residuals 20 40 60 80 100 120 20...
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This note was uploaded on 06/02/2010 for the course IEOR SIEO W4150 taught by Professor Gallego during the Spring '04 term at Columbia.

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Homework Solutions 12 - Solutions to Homework #12 (W4150...

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