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Homework Solutions 12

# Homework Solutions 12 - (W4150 Intro to Probability and...

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Solutions to Homework #12 (W4150 ‘Intro to Probability and Statistics’, S04; special acknowledgements to Aditya V. Prasad) Sec. 11.3. (1) Individual x y 13 29.0 76.7 1 17.3 71.7 14 29.6 78.3 2 19.3 48.3 15 29.9 60.0 3 19.5 88.3 16 29.9 71.7 4 19.7 75.0 17 30.3 85.0 5 22.9 91.7 18 31.3 85.0 6 23.1 100.0 19 36.0 88.3 7 26.4 73.3 20 39.5 100.0 8 26.8 65.0 21 40.4 100.0 9 27.6 75.0 22 44.3 100.0 10 28.1 88.3 23 44.6 91.7 11 28.2 68.3 24 50.4 100.0 12 28.7 96.7 25 55.9 71.7 y = 0.5609x + 64.529 R 2 = 0.1534 0.0 20.0 40.0 60.0 80.0 100.0 120.0 0.0 10.0 20.0 30.0 40.0 50.0 60.0 Arm Strength Dynamic Lift Arm strength vs Dynamic Lift Linear (Arm strength vs Dynamic Lift) a) Using excel, the resulting regression equation is y = 64.529 + 0.5609x . The value of ° = 64.529, while value of ± = 0.5609. b) The point estimate of |30 Y μ = 64.529 + 0.5609 (30) = 81.356

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c) Sec. 11.3. (2) x 77 50 71 72 81 94 96 99 67 y 82 66 78 34 47 85 99 99 68 a) y = 12.062 + 0.7771x ; R 2 = 0.3147 b) |85 Y μ = 12.062 + 0.7771 (85) = 78.11 Sec. 11.3. (2) 17.3 Residual Plot -30 -20 -10 0 10 20 30 0.0 10.0 20.0 30.0 40.0 50.0 60.0 17.3 Residuals 0 20 40 60 80 100 120 0 20 40 60 80 100 120 Midterm Grade Final Grade Midterm vs Final Grade Linear (Midterm vs Final Grade)
Placement Test Course Grade 50 53 35 41 35 61 40 56 55 68 65 36 35 11 60 70 90 79 35 59 90 54 80 91 60 48 60 71 60 71 40 47 55 53 50 68 65 57 50 79 a), b), & c) y = 32.506 + 0.4711x; R 2 = 0.2057 d)

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