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HW-3 Summer 10

# HW-3 Summer 10 - HW-3 Summer 10 Chapter 3 23 30 39 41 44...

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HW-3 Summer 10 Chapter 3 23, 30, 39, 41, 44, 57 (8-th edition) 25, 26, 41, 39, 42, 63 (9-th edition) _______________________________________________________________________ Problem 3-23 (( WileyPlus )) The strategy is to find where the camel is () by adding the two consecutive displacements described in the problem, and then finding the difference between that location and the oasis (). Using the magnitude-angle notation = (24 15 ) + (8.0 90 ) = (23.25 4.41 ) C ∠ - ° ° ° r so (25 0 ) (23.25 4.41 ) (2.5 45 ) B C - = ° - ° = ∠ - ° r r which is efficiently implemented using a vector capable calculator in polar mode. The distance is therefore 2.6 km. (( Mathematica ))

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A G G G 2 4 C o s G 1 5 GG , 2 4 S i n G 1 5 GG G G G ° N G 2 3 . 1 8 2 2 , 3 6 . 2 1 1 6 6 3 G H G G 0 , 8 G G 0 , 8 3 A H G A G G G H G 2 3 . 1 8 2 2 , 1 . 7 8 8 3 4 3 A B G G 2 5 , 0 G G 2 5 , 0 3 H B G A B G A H G 1 . 8 1 7 7 8 , 3 1 . 7 8 8 3 4 3 H B . H B 2 . 5 5 _______________________________________________________________________ Problem 3-30 (( WileyPlus )) The vector equation is r r r r r R A B C D = + + + . Expressing r B and r D in unit-vector notation, we have ˆ ˆ (1.69i 3.63j) m + and ˆ ˆ ( 2.87i 4.10j) m - + , respectively. Where the length unit is not displayed in the solution below, the unit meter should be understood.
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