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Unformatted text preview: HW3 Summer 10Chapter 323, 30, 39, 41, 44, 57 (8th edition)25, 26, 41, 39, 42, 63 (9th edition)_______________________________________________________________________Problem 323((WileyPlus))The strategy is to find where the camel is () by adding the two consecutive displacements described in the problem, and then finding the difference between that location and the oasis (). Using the magnitudeangle notation= (24 15 ) + (8.0 90 ) = (23.25 4.41 )C∠ °∠°∠°rso(25 0 ) (23.25 4.41 )(2.5 45 )B C=∠° ∠° =∠ °rrwhich is efficiently implemented using a vector capable calculator in polar mode. The distance is therefore 2.6 km.((Mathematica))AGGG24 CosGG15GGG, 24 SinGG15GGGGG&NG23.1822,36.211663GHGG0, 8GG0, 83AHGAGGGHG23.1822, 1.788343ABGG25, 0GG25, 03HBGABGAHG1.81778,31.788343HB.HB2.55_______________________________________________________________________Problem 330((WileyPlus))The vector equation is rrrrrRABCD=+++. Expressing rBand rDin unitvector notation, we have ˆˆ(1.69i3.63j) m+and ˆˆ( 2.87i4.10j) m+, respectively. Where the , respectively....
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This note was uploaded on 06/03/2010 for the course PHYS 131 taught by Professor Ibowbi during the Summer '08 term at Binghamton University.
 Summer '08
 IBOWBI
 Physics

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