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Unformatted text preview: HW-3 Summer 10Chapter 323, 30, 39, 41, 44, 57 (8-th edition)25, 26, 41, 39, 42, 63 (9-th edition)_______________________________________________________________________Problem 3-23((WileyPlus))The strategy is to find where the camel is () by adding the two consecutive displacements described in the problem, and then finding the difference between that location and the oasis (). Using the magnitude-angle notation= (24 15 ) + (8.0 90 ) = (23.25 4.41 )C∠ -°∠°∠°rso(25 0 ) (23.25 4.41 )(2.5 45 )B C-=∠° -∠° =∠ -°rrwhich is efficiently implemented using a vector capable calculator in polar mode. The distance is therefore 2.6 km.((Mathematica))AGGG24 CosGG15GGG, 24 SinGG15GGGGG&NG23.1822,36.211663GHGG0, 8GG0, 83AHGAGGGHG23.1822, 1.788343ABGG25, 0GG25, 03HBGABGAHG1.81778,31.788343HB.HB2.55_______________________________________________________________________Problem 3-30((WileyPlus))The vector equation is rrrrrRABCD=+++. Expressing rBand rDin unit-vector notation, we have ˆˆ(1.69i3.63j) m+and ˆˆ( 2.87i4.10j) m-+, respectively. Where the , respectively....
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This note was uploaded on 06/03/2010 for the course PHYS 131 taught by Professor Ibowbi during the Summer '08 term at Binghamton University.
- Summer '08