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Unformatted text preview: According to our denition of N , we know N Geo ( p ) P ( N > 10) = X n =11 p (1p ) n1 = p * (1p ) 10 1(1p ) = (1p ) 10 = 0 . 9396101 . 5.19 , It is a problem of nding a z score given a probability. P ( X > c ) = P ( Z > c12 4 ) = 0 . 1 , and by checking the normal table, we can nd the z score corresponding 0 . 1 is 1.28. So by solving equation c12 2 =1 . 28 , we can compute c = 9 . 44. 5.21 , Dene X := the height of a man; we know that X N (71 , 6 . 25). P ( X > 74) = P ( Z > 3 2 . 5 ) = 0 . 1150697; next question is of computing a conditional probability P ( X > 77  X > 72) = P ( X > 77) P ( X > 72) = . 008197536 . 3445783 = 0 . 02379006 . 2...
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This note was uploaded on 06/05/2010 for the course STAT PStat 120a taught by Professor Rohinikumar during the Spring '10 term at UCSB.
 Spring '10
 RohiniKumar

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