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Unformatted text preview: defective items in a sample of 200 items produced by the process? Solution. We assume that each item is defective with probability p = 1 / 100, independently of other items. Let X be the number of defectives in a sample of 200. Then X ∼ Bin ( n = 200 , p = 1 / 100) with np = 200 × 1 / 100 = 2. Using Poisson approximation, P ( X ≥ 2) = 1P ( X = 0)P ( X = 1) ≈ 1e2 2 0!e2 2 1 1! = 13 e2 = 0 . 594 ....
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This note was uploaded on 06/05/2010 for the course STAT PStat 120a taught by Professor Rohinikumar during the Spring '10 term at UCSB.
 Spring '10
 RohiniKumar
 Binomial, Poisson Distribution, Probability

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