{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

midterm-solutions

# midterm-solutions - Problem 1 Sample space S =cfw_all...

This preview shows pages 1–2. Sign up to view the full content.

Problem 1. Sample space S = { all possible combinations of the two teams that can be formed } . | S | = 10 5 · 15 5 . We assume all possible team combinations are equally likely. 1. Define E = { teams chosen such that Lebron is on company A’s team AND Larry is on company B’s team } . We want to find P ( E ) and we know that P ( E ) = | E | | S | . A team for company A with Lebron in it can be chosen ( 9 4 ) ways. A team for company B with Larry in it can be chosen ( 14 4 ) ways. So | E | = 9 4 · 14 4 . Therefore P ( E ) = | E | | S | = ( 9 4 ) · ( 14 4 ) ( 10 5 ) · ( 15 5 ) . = 1 6 = . 167 . 2. Define F = { teams chosen such that Lebron does not play and Larry does play for company B } . We want P ( F ). A team for company A with Lebron not playing can be chosen ( 9 5 ) ways. A team for company B with Larry playing in it can be chosen ( 14 4 ) ways (as before). Then | F | = 9 5 · 14 4 . Therefore P ( E ) = | F | | S | = ( 9 5 ) · ( 14 4 ) ( 10 5 ) · ( 15 5 ) . = 1 6 = . 167 . Problem 2. Define F i = { firm i is involved } , i = 1 , 2 , 3 , C = { a cost overrun occurs } . We are given P ( F 1 ) = . 5 , P ( F 2 ) = . 2 . P ( C | F 1 ) = . 05 , P ( C | F 2 ) = . 1 , P ( C | F 3 ) = . 15 .

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}