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Quiz 5 - Version 235 Quiz 5 Laude(53755 This print-out...

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Version 235 – Quiz 5 – Laude – (53755) 1 This print-out should have 8 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 5.0 points Approximate the work for the following re- action at 300 K. CH 4 (g) + 2O 2 (g) -→ CO 2 (g) + 2H 2 O( ) 1. 5 kJ correct 2. - 5 kJ 3. 0 kJ 4. 2 . 5 kJ 5. - 2 . 5 kJ Explanation: At room temperature ( 300 K), the product of the RT term in W = - Δ n gas RT is approx- imately 2 . 5 kJ. Since Δ n gas is - 2 for this reaction, the work function is approximately 5 kJ. 002 5.0 points Using the provided bond enthalpy data, cal- culate the change in enthalpy for the following reaction: 2N 2 H 2 (g) + 3O 2 (g) ←→ 4NO(g) + 2H 2 O(g) 1. 1 , 166 kJ · mol 1 2. 1 , 531 kJ · mol 1 3. - 514 kJ · mol 1 correct 4. - 1 , 531 kJ · mol 1 5. - 1 , 166 kJ · mol 1 6. 514 kJ · mol 1 Explanation: Δ H rxn = ΣBE reactants - ΣBE products = 2 · 409 kJ · mol 1 + 4 · 388 kJ · mol 1 +3 · 496 kJ · mol 1 - 4 · 630 kJ · mol 1 - 4 · 463 kJ · mol 1 = - 514 kJ · mol 1 003 5.0 points For this problem assume that the calorime- ter itself absorbs no heat. If we set up a
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